When do you use u-substitution in integration?

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Discussion Overview

The discussion centers around the use of "u-substitution" in integration, exploring when it is appropriate to apply this technique compared to other methods. Participants share their understanding and examples related to this integration method, particularly in the context of preparing for a final exam.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant expresses confusion about when to use u-substitution and seeks guidance on identifying suitable problems for this method.
  • Another participant suggests that a good indicator for using u-substitution is the presence of a function inside the integral whose derivative is also present, providing the example of ∫sin(x)cos(x)dx.
  • A different participant notes that substitution is simpler compared to other techniques like integration by parts and recommends trying simple substitutions first to avoid complications.
  • One participant describes a rule of thumb for u-substitution, indicating that the argument of a more complex function should be of the same "family" as a simpler function, using the example of ∫e^{x^2} 2xdx.
  • Another participant emphasizes that u-substitution is used when it simplifies the computation, illustrating this with the integral ∫√(1-x^2)dx and a trigonometric substitution.

Areas of Agreement / Disagreement

Participants present various perspectives on when to use u-substitution, with no consensus reached on a singular method or rule. Multiple viewpoints and examples are shared, indicating a range of approaches to the topic.

Contextual Notes

Some participants provide specific examples and rules, but there is no agreement on a definitive guideline for identifying when to use u-substitution. The discussion includes assumptions about the familiarity with derivatives and integrals.

JessicaJ283782
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When do you use "u-substitution" in integration?

I understand how to use it, but I'm just getting really confused on when you use it? Is there a way you can look at the problem and tell you need substitution vs. other methods? We have a final coming up, and obviously we won't have too much time to think so any suggestions are appreciated! Thank you!
 
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I think a good indicator that you should use it is if you have a function inside the integral and if you know its derivative, you see the derivative as well.

Take for example

∫sin(x)cos(x)dx.

You probably know that the derivative of sin(x) is cos(x)dx. So in that particular case its easy to call sin(x) u, then du is just the derivative of u, so then your integral becomes ∫u du, which is much more clean and easy to solve.
 
Substitution is among the simpler techniques that can be used, as compared to integration by parts and trig substitutions. I find that it is good to try out the simple substitutions before going on to the more complicated techniques. Being more complicated, they tend to take more time and offer more opportunities for errors.
 
Generally, the rule of thumb for integrating by substitution is having an integrand such that the argument of the more complex function is of the same "family" as the less complex function. For example, take:
\int e^{x^2} \ 2x dx
In this example, the more complex function is the exponential, thus, we will check to see if the argument of the exponential is the same as the other function. The argument of e^{x^2} is x^2, thus \frac{d}{dx} x^2 = 2x, which is a polynomial like the less complex function. On another note, if you have a rational function (a ratio of two polynomials), nine times out of ten, u will be the denominator.
When the argument of the more complex function is not of the same class as the other function, such as
\int e^{x^2} sin(x) dx
you will have to integrate by parts.

I hope this made sense.
 
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You use the "u-substituion" when you think that this change of variable will facilitate the computation for you.

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For example: compute the integral ##\int \sqrt{1-x^2}dx##

Well, I know that ##\cos(\theta) = \sqrt{1-\sin(\theta)^2}##, so if I say that ##x = \sin(\theta)## thus

##\int \sqrt{1-x^2}dx = \int \sqrt{1-\sin(\theta)^2} d\sin(\theta) = \int \sqrt{1-\sin(\theta)^2} \frac{d\sin(\theta)}{d\theta}d\theta = \int \cos(\theta) \cos(\theta) d\theta= \int \cos(\theta)^2 d\theta## and this last integral is easy of compute
 

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