A bob attached to a string becomes slack when the tension in the string (T) reaches zero. This occurs when the gravitational force component (mg cos θ) equals the centripetal force required for circular motion (mv²/r). The discussion emphasizes that the angle (θ) must be considered, particularly whether it remains below or exceeds 90 degrees. If T=0, it indicates that the bob is no longer in circular motion and the relationship between θ and velocity (v) is critical. Understanding these dynamics is essential for analyzing the motion of the bob.
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atavistic
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When does a bob attached to a string become slack?When mgcos@ = mv^2/r?
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?