When does the Inner Product Sum Inequality hold with equality?

Click For Summary

Homework Help Overview

The discussion centers around the inner product space and the conditions under which the Inner Product Sum Inequality holds with equality. Participants are exploring the implications of the Cauchy-Schwarz Inequality and Bessel's Inequality in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the Cauchy-Schwarz Inequality and its implications for the given inequality involving orthonormal vectors. There is uncertainty about the correct application of the inequality and how to proceed from certain steps.

Discussion Status

Some participants have attempted to apply the inequalities to derive the required result, while others express confusion about the steps and seek clarification. There is a sense of progress as some participants believe they are close to a solution, but no consensus has been reached yet.

Contextual Notes

There is mention of a lack of formal instruction on certain aspects of the inequalities being discussed, which may affect the understanding of the participants. Additionally, the original poster expresses concern about the simplicity of their findings, indicating a potential hesitation about their correctness.

JonoPUH
Messages
11
Reaction score
0

Homework Statement


Let V be a real inner product space, and let v1, v2, ... , vk be a set of orthonormal vectors.
Prove
Ʃ (from j=1 to k)|<x,vj><y,vj>| ≤ ||x|| ||y||

When is there equality?

Homework Equations


The Attempt at a Solution



I've tried using the two inequalities given to us in lectures, namely Cauchy-Schwarz Inequality which states

|<v,w>| ≤ ||v|| ||w||

But surely, using this inequality, we get Ʃ (from j=1 to k)|<x,vj><y,vj>| ≤ k(||x|| ||v|| ||y|| ||v|| = k( ||x|| ||y||) since the v are orthonormal!

I understand this is an inequality, and so obviously the inequality above is a better approximation than the one I've just shown, but I'm not sure where to go.

The other inequality is Bessel's Inequality which states

||v||2 ≥ Ʃ|<v, ei>|2 if ei is a set of orthonormal elements.

Thanks
 
Last edited:
Physics news on Phys.org
The space \mathbb{R}^k is an inner product space for the usual inner product. What does the Cauchy-Schwarz inequality say in this special case \mathbb{R}^k??
 
Ok, so according to Wikipedia (I haven't been taught this in lectures), the Cuachy-Schwarz inequality over ℝn is:

(Ʃ xiyi)2 ≤ Ʃxi2 Ʃyi2

Do I replace multiplication with inner products? I've tried that, but I must be doing something wrong.


(Ʃ <x,vj>)2 ≤ Ʃ<x,x> Ʃ<vj,vj> = k||x||2Ʃ<vj,vj> = k||x||2 x k since ||vj||=1 ?
But then where should I go from here, if here is where I should be?
Sorry
 
JonoPUH said:
Ok, so according to Wikipedia (I haven't been taught this in lectures), the Cuachy-Schwarz inequality over ℝn is:

(Ʃ xiyi)2 ≤ Ʃxi2 Ʃyi2

Do I replace multiplication with inner products? I've tried that, but I must be doing something wrong.


(Ʃ <x,vj>)2 ≤ Ʃ<x,x> Ʃ<vj,vj> = k||x||2Ʃ<vj,vj> = k||x||2 x k since ||vj||=1 ?
But then where should I go from here, if here is where I should be?
Sorry

The version of Cauchy-Schwarz that is most standard is actually

\sum_{k=1}^n |\alpha_k\beta_k|\leq \sqrt{\sum_{k=1}^n |\alpha_k|^2}\sqrt{\sum_{k=1}^n |\beta_k|^2}

Now, apply this on your original problem

\sum_{k=1}^n |&lt;x,v_k&gt;&lt;y,v_k&gt;|
 
Thank you so much! I think I have it, although it seems very easy, which always seems suspicious to me in maths. Here goes:

Ʃ |<x,vj><y,vj>| ≤ √(Ʃ<x,vj>2) √(Ʃ<xy,vj>2)

Then by Bessel's Inequality

√Ʃ<x,vj>2√Ʃ<xy,vj>2 ≤ √||x||2 √||y||2

So Ʃ |<x,vj><y,vj>| ≤ ||x|| ||y|| as required!
 
Last edited:
That's it!
 
Thank you very much! You've made my night!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K