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When does the mass of object comes into projectile motion equations?

  1. Oct 5, 2013 #1
    A 78g basketball is launched at an angle is 52.4 degrees from a distance of 14.7 m from the basket. Ball is released at the same height as basket (10 feet). Acceleration is 9.8 m/s2. What speed will the player need to give the ball?

    I know that I'm supposed to use the kinematics and trig to figure out the other sides to the triangle.

    I found the hypotenuse by doing 14.7 / (cos 52.4) to get 24.09. The last remaining side is found by using (14.7 tan 52.4).

    Now what? Where do I put the mass of the basketball into the equation?
  2. jcsd
  3. Oct 5, 2013 #2

    Simon Bridge

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    14.7m is the horizontal distance to the basket - which triangle did you compute the hypotenuse for? Why do you need it?

    Everywhere you see an "m" or other symbol indicating that mass goes there.

    Instead of worrying about the equations and what you are "supposed" to do - why not consider the physics of the situation?
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