A 78g basketball is launched at an angle is 52.4 degrees from a distance of 14.7 m from the basket. Ball is released at the same height as basket (10 feet). Acceleration is 9.8 m/s2. What speed will the player need to give the ball? I know that I'm supposed to use the kinematics and trig to figure out the other sides to the triangle. I found the hypotenuse by doing 14.7 / (cos 52.4) to get 24.09. The last remaining side is found by using (14.7 tan 52.4). Now what? Where do I put the mass of the basketball into the equation?