When is following equation true?

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The equation \sqrt{c^2+14c+49} = c + 7 is true under specific conditions related to the absolute value of c + 7. The simplification leads to |c + 7| = c + 7, which is valid when c \geq -7. The discussion highlights the importance of recognizing that \sqrt{x^2} = |x| rather than x, particularly for negative values of x.

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Rectifier
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1. The problem

When is the following equation true
## \sqrt{c^2+14c+49} = c + 7##

a) for all real c
b) for ## c \geq -7 ##
c) for ## c < -7##
d) c > 0
e) c < 0

The attempt 1
I know that the root of ## c^2+14c+49 = 0 ## is ## c = -7 ## and that this sqr-root is only defined for positive numbers. Thus the equation is true only when the stuff below the root is positive. But that stuff is always positive...

The attempt 2
## \sqrt{c^2+14c+49} = c + 7 \\ \sqrt{(c+7)^2} = c + 7 \\ c+7 = c + 7 \\ ##
Thus this equation is true for all real c:s. But somehow this is wrong.
 
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Look at your last step in Attempt 2. Are you sure that it's always the case that ##\sqrt{x^2}=x##, given that the convention is that the positive square root is always implied by the square root sign? What about if x=-1? What happens if you start with -1, square it and then take the square root (which is by convention positive). Do you end up with the number you started with?
 
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andrewkirk said:
What makes you you think your answer is wrong?
The answer in my book :)
 
Rectifier said:
## \sqrt{c^2+14c+49} = c + 7 \\ \sqrt{(c+7)^2} = c + 7 \\ c+7 = c + 7 \\ ##
The problem is in that last step, because ##\sqrt{x^2} \neq x##. Can you see why?

Rectifier said:
The answer in my book :)
What about trying it yourself?
 
Yeah, sorry, my first answer was too quick. I hope my redraft makes more sense.
 
DrClaude said:
The problem is in that last step, because ##\sqrt{x^2} \neq x##. Can you see why?What about trying it yourself?

Yeah. Because negative x:es give different results.

How can I implement that in my problem?
 
Rectifier said:
Yeah. Because negative x:es give different results.

How can I implement that in my problem?
You have to use absolute values.
 
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So basically |c + 7| = c + 7
 
Rectifier said:
So basically |c + 7| = c + 7
Yes. You should be able to convert that to a condition on ##c##.
 
  • #10
Rectifier said:
So basically |c + 7| = c + 7
DrClaude said:
Yes. You should be able to convert that to a condition on ##c##.
To be clear, |c + 7| is not equal to c + 7, as when, for example, c = -8. I believe that @DrClaude is in agreement with this, but the casual reader might misinterpret his comment.

##\sqrt{(c + 7)^2} \neq c + 7##
but
##\sqrt{(c + 7)^2} = |c + 7|##
 
  • #11
Mark44 said:
To be clear, |c + 7| is not equal to c + 7, as when, for example, c = -8. I believe that @DrClaude is in agreement with this, but the casual reader might misinterpret his comment.
Of course I agree :smile:

My point is that the question starts with:

When is the following equation true
##\sqrt{c^2+14c+49} = c + 7##

which is simplified to:

When is the following equation true
##| c+ 7| = c + 7##

from which it is easy to get a condition on ##c## for the original equation to be true.
 
  • #12
Use the definition of absolute value: |a|= a if a\ge 0, |a|= -a if a&lt; 0.
 

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