When Is Net Torque Equal to Zero?

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Homework Help Overview

The discussion revolves around the concept of net torque in a physics context, specifically regarding when net torque equals zero for rotating bars depicted in a diagram. Participants are exploring the conditions under which torque calculations yield a net result of zero.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand how to calculate torque from various forces acting on the bars and are questioning the relevance of force cancellation. There are discussions about the signs of torques and the specific values derived from the forces in the diagrams.

Discussion Status

The conversation is ongoing, with some participants providing guidance on how to calculate torque and others expressing confusion about specific values and their implications. There is a collaborative effort to clarify the calculations and interpretations of the diagrams.

Contextual Notes

Participants are working with a specific diagram that is referenced but not visible in the thread. There are mentions of potential typos in force values, which may affect the calculations being discussed.

jaded18
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when is net torque equal to 0??

Each of the four bars shown can rotate freely in the horizontal plane about its left end. For which diagrams is the net torque equal to zero?
http://session.masteringphysics.com/problemAsset/1003642/26/170580B.jpg
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i know that for torque to equal O angular momentum = I(omega) is constant and conserved... but I'm having trouble applying this to the diagram ... i thought D would be part of the answer because the Newtons all cancel out ... help??
 
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Whether the force cancels out doesn't matter. Just add up all the torques from each force to get the total.
 
anyone else can help me? i need more to go on...
 
Do you know how to calculate the torque from each force? Since the forces are all perpendicular to the distance (r) it's simply T = rF. (Be sure to give clockwise and counterclockwise torques different signs.)
 
let's do it this way. look at diagram a. if torque = rF then torque for the four forces from left to right is 0, 6(L/4), 1(3L/4), and 7(L)?? maybe if i know how to solve for one i can do it on my own
 
I don't know where you got the 6 N force, I see 8 N. Maybe a typo?

Here's how I would do it. First, I'll call counter-clockwise torques positive and clockwise torques negative. Here's what I get for each force in A:
0 + 8(L/4) - 1(3L/4) - 7(L) = 2L -3L/4 - 7L = -5.75L (which is sure not zero. Next!)
 
thanks :)
 

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