When Should Parametric Equations Be Used to Calculate Curve Length?

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SUMMARY

The discussion focuses on calculating the arc length of the function \( f(x) = \frac{1}{3}(x^2 + 2)^{3/2} \) over the interval [0, a]. The participants explore both parametric equations and direct integration methods to find the arc length. The final result for the arc length is established as \( s = \frac{a^3}{3} + a \). The conversation also addresses the conditions under which parametric equations should be utilized for curve length calculations.

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  • Understanding of calculus, specifically integration techniques.
  • Familiarity with parametric equations and their applications.
  • Knowledge of arc length formulas in Cartesian coordinates.
  • Ability to differentiate functions and apply the chain rule.
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  • Study the derivation of arc length using parametric equations.
  • Learn how to apply the arc length formula for polar coordinates.
  • Explore advanced integration techniques, such as integration by parts.
  • Investigate the applications of parametric equations in physics and engineering.
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Students and professionals in mathematics, particularly those studying calculus, as well as educators looking to enhance their understanding of curve length calculations using both parametric and Cartesian methods.

karush
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Find the arc length of
$$f (x)=(1/3)(x^2 +2)^{3/2}$$
On the interval [0, a]

The parametric I got

$$y=t$$
$$x=\sqrt{(3t)^{2/3}-2}$$

I proceeded but didnt get the answer of

$$a+\frac{a^3}{3}$$
 
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Re: Lenght of a curve

I wouldn't bother with parametrization...:)

We have:

$$f(x)=\frac{1}{3}\left(x^2+2\right)^{\frac{3}{2}}$$

Hence:

$$f'(x)=x\sqrt{x^2+2}$$

And so the arc-length $s$ will be given by:

$$s=\int_0^a\sqrt{1+\left(x\sqrt{x^2+2}\right)^2}\,dx$$

Can you proceed?
 
$$\displaystyle
s=\int_0^a\sqrt{1+\left(x\sqrt{x^2+2}\right)^2}\,dx
=\int_{0}^{a} \left({x}^{2}+1\right)\,dx
=\frac{a^3}{3}+a
$$

When do we use parametrics for length of curve
 
Last edited:

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