When should the Parallel Axis Theorem be used in mechanics?

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SUMMARY

The discussion centers on the application of the Parallel Axis Theorem (PAT) in mechanics, specifically in scenarios involving rolling objects. The user successfully applied PAT to a hoop rolling down an incline but encountered confusion when analyzing a spool being pulled by a string. The key takeaway is that the choice of the axis of rotation significantly influences the use of PAT; if the center of mass is chosen, the moment of inertia (I) and torques are calculated about that point, eliminating the need for PAT. Conversely, if the point of contact with the ground is selected as the axis, PAT must be applied to determine the rotational inertia about that point.

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  • Understanding of the Parallel Axis Theorem (PAT)
  • Knowledge of rotational dynamics and moment of inertia
  • Familiarity with torque calculations
  • Basic mechanics principles involving rolling motion
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Students and professionals in physics and engineering, particularly those focusing on mechanics and dynamics involving rotational motion and the application of the Parallel Axis Theorem.

amcavoy
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I know what the parallel axis theorem is, but I'm a little confused about when to use it. I recently had a problem where a hoop was rolling down an incline where I used the parallel axis theorem to find the translational acceleration and got it correct. However, I had a problem about a spool being pulled by a string (think of a yo-yo being pulled on the ground), and when I set up the equations I got the wrong answer using the P.A.T. For instance, I had:

[tex]F-F_{S}=ma[/tex]

[tex]RF_{S}-rF=I_{CM}\alpha[/tex]

Why isn't the ICM instead IP? I have solved the problem already and know the answer, I just can't see why the parallel axis theorem is not used. LINK: http://show.imagehosting.us/show/971155/0/nouser_971/T0_-1_971155.jpeg

Thank you for your help.
 
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I just depends on what you take as your axis of rotation. If you take the center of mass, then I and torques will be about that point. (And you'll have no need for the parallel axis theorem.)

But you are certainly free to use the point of contact with the floor as your instantaneous axis of rotation. But if you do, be sure to take torques about that point as well. In this case you'll need to use the parallel axis theorem to find the rotational inertia about that point.

Done correctly, you'll get the same answer either way.
 

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