When will velocities of the trains equal?

  • Thread starter Thread starter Entr0py
  • Start date Start date
  • Tags Tags
    Trains
Click For Summary
SUMMARY

The discussion centers on determining the time at which the velocities of two trains become equal, specifically Train A, which travels at a constant velocity of x m/s, and Train B, which accelerates from rest after a 20-second delay. The key equations involve calculating the distance traveled by Train A during the first 20 seconds and the acceleration of Train B. The problem requires understanding the relationship between distance, velocity, and acceleration to find the moment when Train B's velocity matches that of Train A.

PREREQUISITES
  • Understanding of kinematic equations for constant acceleration
  • Knowledge of velocity and acceleration concepts
  • Ability to solve algebraic equations
  • Familiarity with the concept of relative motion
NEXT STEPS
  • Study kinematic equations, specifically for uniformly accelerated motion
  • Learn how to set up and solve equations involving relative velocities
  • Explore graphical representations of motion to visualize acceleration and velocity
  • Investigate real-world applications of relative motion in train systems
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples of motion and acceleration concepts.

Entr0py
Messages
102
Reaction score
1

Homework Statement


A train having a velocity of x m/s is caught by a train accelerating from zero 20 seconds after the second train starts. At what time were their velocities equal?

Homework Equations

The Attempt at a Solution


I was thinking that you'd have to assume that the train with x velocity is traveling with constant velocity and that the second train starts at t=t-20 s. However, I'm confused as to how I would find when their velocities would be equal.
 
Physics news on Phys.org
How far does the first train travel?
 
So in 20 s, the first train has traveled x=x0+v0t+.5at^2. well I assumed it started from rest, so x=.5a(400) or 200a m.
 
I'd call that the second train from my reading of the problem statement. Let's tidy up the statement a bit so we're both discussing the same trains. "Train A is moving at a constant velocity of x m/s. As it pulls even with Train B, Train B accelerates from 0 at a constant rate, and pulls even with A after 20 seconds. At what time are the two velocities equal?"

Now, I ask how far does Train A travel?
 
I'm sorry I'm confused?
 
Entr0py said:
I'm sorry I'm confused?
You need to say exactly what is confusing you. Bystander's description of the problem is correct. I'll try to make it more concrete.
At t=0, both trains are at s=0. Train A is moving at constant speed x, train B is stationary.
Train B then accelerates at some unknown constant (we must assume) rate a. At t=20, the trains have traveled the same distance. Train B must now be moving faster than train A.
At what time was train B moving at speed x?

Bystander is asking you, first, how far train A traveled in those 20 seconds.
 

Similar threads

  • · Replies 84 ·
3
Replies
84
Views
5K
Replies
3
Views
975
Replies
20
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K