When working out the Uncertainties, what to do with the constants?

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Homework Help Overview

The discussion revolves around calculating uncertainties in physics, specifically in the context of the equation Q=mcT, where Q is heat, m is mass, c is a constant, and T is temperature. Participants are exploring how to handle constants when determining uncertainties in measurements.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions how to treat the constant c in the uncertainty calculation for Q=mcT, particularly whether to include it in the percentage uncertainties of m and T. Other participants discuss the general practice of ignoring constants with small uncertainties and whether this applies to different equations, such as v=2as.

Discussion Status

Participants are actively engaging with the topic, with some providing insights on when to consider constants in uncertainty calculations. There is a recognition that the accuracy of constants can vary based on the context of the experiment, leading to further questions about specific cases.

Contextual Notes

Participants note that the uncertainty of constants is typically small compared to experimental uncertainties, and there is an emphasis on the need for the constant's uncertainty to be comparable to the experimental uncertainty for it to be relevant in calculations.

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Q=mcT, variables with uncertainties are m and T.
If it were only Q=mT, the %uncertainty of Q would be %uncertainty of m + % uncertainty of T.

But c=constant (no uncertainties), so what is the uncertainty of Q when Q=mcT? Do you just multiply the constant to the %uncertainties of m and T?
What generally happens to constants when working out uncertainties?
 
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You would normally ignore it, as the value of the constant found in tables would have a very small uncertainty.
Any uncertainty in the constant would need to be of the same order of magnitude as your experimental uncertainty for it to be necessary to include it.
In your example, if it was water you were using, the value of c can be found from tables to be 4186 J/kg. This is presumably accurate to over one part in 4000. Much more than your readings.
If your experiment used data that was more accurate than this, you would need to get the value of c to even greater accuracy.
 
Oh ok I see...
so eg. v=2as,
then would I need to multiply the 2 to the uncertainties of a and s, or would I ignore it like you said?
 
In that formula, just add the % uncertainties in the things you measure. Ignore the 2.
It is the uncertainty in the measured values that you need to account for.
 
ok, thanks so much!
 

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