Where can I learn to type math script(?)

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Homework Help Overview

The discussion revolves around learning how to format mathematical expressions in a forum setting, particularly in relation to a professor's email that contained complex mathematical notation. The subject area includes mathematical typesetting and communication in an online environment.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants express confusion about how to properly format mathematical expressions, questioning the methods for achieving subscripts and square roots in their posts. There are attempts to clarify the use of specific tags for formatting.

Discussion Status

Some participants have provided guidance on using specific formatting tags, while others are exploring their understanding of the process. There is an ongoing exchange about the effort required to format posts correctly, indicating a shared interest in improving communication of mathematical ideas.

Contextual Notes

Participants note the challenges of translating complex mathematical notation into a format suitable for the forum, highlighting the need for clarity in communication. There is also mention of a misunderstanding regarding the original post's intent.

GcSanchez05
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I am just posting this because my prof sent me an email with weird letters and I want to see if i can read it here...Please disregard unless you can tell me where I can go to copy and paste this so it makes sense

WLOG assume both secuences are bounded by the same number M > 0. Then, choose \epsilon' = (\epsilon)/(2M). For \epsilon' there is n_1, and n_2 such that for
n, m > n_1 ---> |x_n - x_m|< \epsilon' (the sequence <x_n> is Cauchy)
as well as
n, m > n_2 ---> |y_n - y_m| < \epsilon' (<y_n> is Cauchy)
But then for n_0 = max {n_1, n_2} we have
|x_ny_n - x_my_m| < M(|x_n - x_m| + |y_n - y_m|) < M(\epsilon' + \epsilon')
= M((\epsilon)/(2M) + (\epsilon)/(2M)) = \epsilon.
Done.
 
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AH! It didn't work...
 
GcSanchez05 said:
I am just posting this because my prof sent me an email with weird letters and I want to see if i can read it here...Please disregard unless you can tell me where I can go to copy and paste this so it makes sense

WLOG assume both secuences are bounded by the same number M > 0. Then, choose \epsilon' = (\epsilon)/(2M). For \epsilon' there is n_1, and n_2 such that for
n, m > n_1 ---> |x_n - x_m|< \epsilon' (the sequence <x_n> is Cauchy)
as well as
n, m > n_2 ---> |y_n - y_m| < \epsilon' (<y_n> is Cauchy)
But then for n_0 = max {n_1, n_2} we have
|x_ny_n - x_my_m| < M(|x_n - x_m| + |y_n - y_m|) < M(\epsilon' + \epsilon')
= M((\epsilon)/(2M) + (\epsilon)/(2M)) = \epsilon.
Done.

GcSanchez05 said:
AH! It didn't work...

Note that you can preview your posts before posting them to see if they are going to work. Make sure you have pressed the Advanced button under the edit box. Also notice the [itex]\Sigma[/itex] icon above the edit box that will help you with entering symbols.

[Edit] Nevermind. I think I misunderstood your post.
 
Well I don't mean just symbols and greek letters...
Like how would i get {a_n} to appear with the n as an subscript or like a square root to appear instead of typing sqrt(x) or whatever?
 
It's a pain, but you can use the quote button, then edit his text by putting (itex)(/itex) tags around all the math expressions. But use [] and [] instead of the round parentheses; I just put them in so you could see them. Then preview the post. Here's a sample:

[itex]n, m > n_1 ---> |x_n - x_m|< \epsilon[/itex]

Right click on it to see it.
 
GcSanchez05 said:
I am just posting this because my prof sent me an email with weird letters and I want to see if i can read it here...Please disregard unless you can tell me where I can go to copy and paste this so it makes sense

WLOG assume both sequences are bounded by the same number M > 0. Then, choose [itex]\epsilon' = (\epsilon)/(2M)[/itex]. For [itex]\epsilon'[/itex] there is [itex]n_1 and n_2[/itex] such that for
[itex]n, m > n_1 ---> |x_n - x_m|< \epsilon'[/itex] (the sequence [itex]<x_n>[/itex] is Cauchy)

as well as

[itex]n, m > n_2 ---> |y_n - y_m| < \epsilon'[/itex] (<y_n> is Cauchy)

But then for [itex]n_0[/itex] = max {[itex]n_1, n_2[/itex]} we have

[itex]|x_ny_n - x_my_m| < M(|x_n - x_m| + |y_n - y_m|) < M(\epsilon' + \epsilon')<br /> = M((\epsilon)/(2M) + (\epsilon)/(2M)) = \epsilon[/itex]
Done.


Okay, so everytime I see post like that, that means someone took there time to type up there post like that?? I figured there was an easier way to do it lol
 
GcSanchez05 said:
Okay, so everytime I see post like that, that means someone took there time to type up there post like that?? I figured there was an easier way to do it lol

Yes. You've got it figured out.
 

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