Where did the expansion for particle accelerators come from?

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SUMMARY

The expansion for the potential of axial traveling beams in particle accelerators is derived from the Laplace Equation in cylindrical coordinates, specifically referenced in "Particle Accelerators" by Stanly Livingston and Blewett. The relevant equations, particularly Eq 5-16 on page 101, stem from the charge-free condition where charge density ρ = 0. The approximation for paraxial electric fields is detailed, leading to specific coefficients for the potential function. For further insights, readers are directed to page 111, Eq 6.2 in the ebook "Principles of Charged Particle Acceleration" by Humphries.

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  • Understanding of Laplace's equation in cylindrical coordinates
  • Familiarity with potential functions in electrostatics
  • Knowledge of paraxial approximation techniques
  • Basic concepts of particle acceleration physics
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  • Study the derivation of Laplace's equation in cylindrical coordinates
  • Explore the implications of charge density in electrostatic potentials
  • Investigate paraxial electric field approximations in particle accelerators
  • Read "Principles of Charged Particle Acceleration" by Humphries for advanced concepts
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In "Particle Accelerators" book of Stanly Livingston I saw attached potential expansion for the potential of axial traveling beam of particles throght a electrostatic lense. I want to know where this expansion came from? Which expansion is being used and how?
 

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In the book "Particle Accelerators" by Livingston and Blewett on page 101, Eq 5-16 is derived from the Laplace Equation in cylindrical coordinates on page 98 Eq 5-6 with ρ=0.

In a charge-free region, the potential V(r,z) with axial symmetry must satisfy Laplace's equation with charge density ρ =0

Laplace's equation in cylindrical coordinates is then

[tex]\frac{1}{r}\cdot\frac{\partial}{\partial r}[r\frac{\partial V(r,z)}{\partial r}]+\frac{\partial^2V(r,z)}{\partial z^2} = 0[/tex]

The following approximation is useful for approximating paraxial electric fields:

[tex]V(r,z)=V(0,z)+A r\frac{\partial V}{\partial z}+ B r^2\frac{\partial^2 V}{\partial z^2} + C r^3\frac{\partial^3 V}{\partial z^3}+ D r^4\frac{\partial^4 V}{\partial z^4}[/tex]

where the partial derivatives are evaluated on the axis. Substituting the second equation into the first yields A = C = 0, and B = -1/4 and D = +1/64.
To see further discussion, look at page 111 Eq 6.2 in the free downloadable ebook by Humphries "Principles of charged Particle Acceleration":

http://www.fieldp.com/cpa.html

Bob S

test Latex equations here http://www.equationsheet.com/textoimage.php
 
Thanks Bob. Great job.
 

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