Edwardy
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- Homework Statement
- I need to present Fay and Fax using Fa and cos(a) and sin(a). I seem to be missing a minus, why?
- Relevant Equations
- None
The discussion centers on the representation of vector components in the third quadrant, specifically addressing the vector FA and its components FAx and FAy. Both components are negative due to their direction in the third quadrant, where angles are expressed as θ = 180 + α or θ = 360 - α. The distinction between vector magnitude and direction is emphasized, clarifying that while components can be negative, the magnitudes are conventionally positive. This understanding is crucial for accurately representing vectors in multi-dimensional physics.
PREREQUISITESStudents of physics, particularly those studying mechanics, educators teaching vector analysis, and anyone seeking clarity on vector representation and trigonometric applications in multiple dimensions.
There are two ways to think of this.Edwardy said:Homework Statement:: I need to present Fay and Fax using Fa and cos(a) and sin(a). I seem to be missing a minus, why?
Relevant Equations:: None
View attachment 315305
Thank you,topsquark said:There are two ways to think of this.
1) The vector ##F_A## is in the 3rd Quadrant. So both of its vector components will point in the negative directions, thus ##F_{Ax}## and ##F_{Ay}## will be negative.
2) Again, the vector ##F_A## is in the 3rd Quadrant. So the angle it makes with the +x axis is actually ## \theta = 180 + \alpha##. (Or, equivalently, ##\theta = 360 - \alpha ##.) In the 3rd Quadrant ##sin( \theta )## and ##cos( \theta )## are negative.
-Dan
I have left the vector notation off here (it messes up the LaTeX for some reason.) The vector ##F_A## has vector components ##F_{Ax}## and ##F_{Ay}##. These are vectors so they have magnitude and direction. The magnitudes of the vectors ##\mid F_A \mid = F_A##, ## \mid F_{Ax} \mid = F_{Ax}##, ## \mid F_{Ay} \mid = F_{Ay}## are just numbers, taken to be positive by convention. The x component of ##F_A## is ##F_{Ax} ( - \hat{i} )## where ##\hat{i}## is the unit vector in the +x direction. The negative is attached to the unit vector direction, not the magnitude.Edwardy said:Thank you,
I have one more question though. From my understanding, we are not thinking of Fa as a vector here (hence the arrow above it is missing), so why wouldn't Fa be negative itself? It would have both negative coordinates?
Welcome!Edwardy said:Homework Statement:: I need to present Fay and Fax using Fa and cos(a) and sin(a). I seem to be missing a minus, why?
Relevant Equations:: None