Where does the missing energy go in an inelastic collision?

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SUMMARY

The discussion centers on the energy transformation during an inelastic collision, specifically when two equal masses collide and stick together. It is established that, according to the conservation of momentum, the final velocity of the combined mass is half of the initial velocity of the moving mass. The kinetic energy after the collision is half of that before the collision, with the missing energy primarily dissipated as heat, sound, and deformation work. The process may also involve damped oscillations, indicating energy dissipation over time.

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Lukeblackhill
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Morning,

I was thinking about a simple example of inelastic collision: A ball of mass m1, moving with a certain velocity v1, collides and sticks with another mass m2, at rest. The whole system (m1 + m2) will then move with a certain speed v3.

If we take m1=m2, so that after the collision we have a single mass of 2m1 mass, by the conservation of momentum, v3 = v1/2. If we work out the kinetic energy of the system before and after the collision, we have K(after) = K(before)/2.

The question is...where does the other half of kinetic energy goes to? In such a collision, must we necessarily expect losses in terms of heat and sound, or can we find that other half transformed in some sort of "gluing energy"?

Cheers,
Luke.
 
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'All' the missing energy will go into the deformation process, heat and sound. It can require a lot of work to deform materials. There will often be some damped oscillation during the process, in which the energy is dissipated over a significant length of time.
 
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sophiecentaur said:
'All' the missing energy will go into the deformation process, heat and sound. It can require a lot of work to deform materials. There will often be some damped oscillation during the process, in which the energy is dissipated over a significant length of time.
Thank you, @sophiecentaur.
 

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