Where Is the Electric Potential Minimum on a Circle in a Uniform Electric Field?

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Epiclightning
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The electric field at the origin is along the positive x axis. A small circle is drawn with the center at the origin cutting the axes at points A, B, C, and D having coordinates (a,0), (0,a), (-a,0), (0,-a), respectively. Out of the points on the periphery of the circle, the potential is minimum at _______?
(a) A (b) B (c) C (d) D

After drawing the diagram, I see that the electric field is directed towards the right along the x-axis (towards A). However, electric potential = KQ/r, and here Q and r are constant for all four points. I don't see how any point could have "minimum" potential.
 
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Hello Epic, welcome to PF :)

Did you notice the template ? Better use it.

However:
Your electric potential expression isn't applicable here. There is no mention of Q !

You want to make use of a different relationship between E and V.
In the template, there is room for such equations under 2) relevant equations.
 

Homework Statement


The electric field at the origin is along the positive x axis. A small circle is drawn with the center at the origin cutting the axes at points A, B, C, and D having coordinates (a,0), (0,a), (-a,0), (0,-a), respectively. Out of the points on the periphery of the circle, the potential is minimum at _______?
(a) A (b) B (c) C (d) D

Homework Equations


V = -E dr

The Attempt at a Solution


After drawing the diagram, I see that the electric field is directed towards the right along the x-axis (towards A). But how will integrating the above equation give me the "minimum" potential necessary?
Thanks for the help
 
Much better !
Actually, it's ##{\bf d}V = -\vec E\cdot d\vec r\,##. You integrate and get ##\Delta V##, which happens to be just the one you are after !