Where Is the Resultant Force Applied on a Square Plate?

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Homework Help Overview

The problem involves determining the point of application of the resultant force on a square plate subjected to three forces. The context is centered around the principles of force and torque in mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the nature of the resultant force and its application, with some suggesting to analyze the torque about a specific point. There is a mention of breaking down forces into components to better understand their effects.

Discussion Status

The discussion is ongoing, with some participants providing insights into the relationship between torque and the resultant force. There is recognition of the correct direction and magnitude of the resultant force, but the exact location remains to be clarified.

Contextual Notes

Participants are exploring the implications of torque and the conditions under which the resultant force can be determined, indicating a need for further clarification on the setup and assumptions regarding the forces applied.

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Homework Statement



Three forces are applied to a square plate of side a. The point of application (on side BC) of the resultant force is ?

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The Attempt at a Solution



Resultant force acts along AC with magnitude 2F. How to find the point of application that too on a given side?
 

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The resultant force does not act along a line from A to C. The resultant force is the force that is the vector sum of the individual forces, the line of action of which produces the same torque about any point as the sum of the torques of the individual forces about that point. It is often best to first break each force into its component forces.
 
To make things easier, look at the torque about point A.

You do have the correct direction (to the right) and magnitude for the resultant force, just not the correct location.
 
PhanthomJay said:
the line of action of which produces the same torque about any point as the sum of the torques of the individual forces about that point.

I did not know about this. Now the problem is a piece of cake :smile:
Thanks!
 

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