Where on the x-axis is the potential zero

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The discussion revolves around solving for the locations on the x-axis where electric potential is zero due to two charges: -1.9 × 10^-9 C at the origin and 9.4 × 10^-9 C at x = 3 m. The user attempted to set the potentials equal by using the formula kq1/r1 = kq2/r2, but made an error in calculating r1. They correctly noted that r represents the distance from each charge to the point where potential is zero. The solution requires careful consideration of the distances from both charges to find the correct positions on the x-axis. The user seeks clarification and assistance in resolving their calculations.
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Homework Statement


Is this question on electric potential solvable? I've tried everything. any ideas?
A charge of -1.9 × 10-9 C is at the origin and a charge of 9.4 × 10-9 C is on the x-axis at x = 3 m. At what two locations on the x-axis (xpositive, xnegative) is the potential zero?





Homework Equations





The Attempt at a Solution


heres what i did...

kq1/r1 = kq2/r2

first i canceled k because its on both sides, and a constant..
then i solved for r1...

r1 = r2q1/q2

then i added the values...

r1 = 3(-1.9e-9) / (9.4e-9)

answer = .606

this is wrong... please help! thanks
 
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Think about what your variables r1 and r2 mean here.
 
r is the distance from the charge where the potential is zero isn't it?
 

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