1. The problem statement, all variables and given/known data Two parallel-plate capacitors have the same plate area. Capacitor 1 has a plate separation twice that of capacitor 2, and the quantity of charge you place on capacitor 1 is six times the quantity you place on capacitor 2. How do the potential differences across each of the two capacitors compare to each other? (V1/V2 = ?) 2. Relevant equations I tried two different approaches: V(A->B) = -W(A->B)/qtest = -(integral of E*dl from A to B) V = q/C C = εA/d 3. The attempt at a solution q1 = 6q2 r1 = 2q2 V1/V2 = (kq1/r1^2)*r1 / (kq2/r2^2)*r^2 = (6q2/2r2)/(q2/r2) = 3 This is not correct. C1/C2 = d1/d2 = 2 V = q/C = 6/2 = 3 I must be misunderstanding potential difference but I'm not sure where I'm going wrong.