Where Should the Pivot Be Placed for Balance on a Seesaw?

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Homework Help Overview

The discussion revolves around a seesaw problem involving two individuals, Harry and Gretchen, with different weights, and the challenge of determining the correct pivot point for balance on an 8.00 m long seesaw.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the use of torque equations to find the distances from the pivot for both individuals. There are attempts to apply formulas related to forces and distances, but some participants express uncertainty about how to isolate variables or apply the equations correctly.

Discussion Status

Some participants have provided equations and suggested methods for balancing the seesaw, while others are questioning the assumptions and values needed for the calculations. There is an ongoing exploration of the relationships between the forces and distances involved.

Contextual Notes

Participants note the importance of significant figures in their answers and the need to clarify the distances from Harry when setting up the equations. There is also mention of the total length of the seesaw and the requirement for two equations to solve for the unknowns.

uno
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1. Harry, who weighs 360 N, and 170 N Gretchen are about to play on a 8.00 m long seesaw. He sits at one end and she at the other. Where should the pivot be located if they are to be balanced?



2. F1R1 = F2 R2; F1=360N F2 = 170 N. The problem gives the total length, and I know I need to find out the distance of Gretchen first, but I can't seem to figure it out. I have also used the formula (M1*g)R1 = (M2*g)R2, but again I'm not sure how to figure out the distance of Gretchen.



3. I tried to use this formula to figure out Gretchen's distance. To = r (mass).

530 = 170 (8) = 3.12, but that answer is incorrect. Please help.
 
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I forgot to include:

They are looking for the distance in meters from Harry.

Thanks
 
uno said:
1. Harry, who weighs 360 N, and 170 N Gretchen are about to play on a 8.00 m long seesaw. He sits at one end and she at the other. Where should the pivot be located if they are to be balanced?



2. F1R1 = F2 R2; F1=360N F2 = 170 N. The problem gives the total length, and I know I need to find out the distance of Gretchen first, but I can't seem to figure it out. I have also used the formula (M1*g)R1 = (M2*g)R2, but again I'm not sure how to figure out the distance of Gretchen.



3. I tried to use this formula to figure out Gretchen's distance. To = r (mass).

530 = 170 (8) = 3.12, but that answer is incorrect. Please help.

Let L be the length from Harry. Then if it balances doesn't

360N * L = 170N * (8 - L) ?
 
In order to figure out the distance of Harry, don't we need to figure out the distance of Gretchen? I'm not sure what valut to put in for L where you have 8-L.
 
Uno: You have two unknowns R1, R2, so you require two equations for a solution:
Balance the torque moments:
F1*R1 = F2*R2,
and
R1+R2=8

Then solve for R1 or R2:
R1=(F2/(F1+F2)) * 8, the pivot is 2.57M from the larger force. Note the three significant figures in the answer. You were given 3 sig figs in the problem, be sure to include 3 in your answer or a tough TA/Prof might ding you.
 

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