Where the energy goes in half wave rectifier?

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waqarrashid33
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Half wave rectifier based on the principle of PN junction diode convert either possitive or negative portion of AC current But i am confused here that when the portion of current on which the diode is reverse biased current is almost zero then where the energy of that portion goes?
 
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Are you referring to the reverse leakage current?

I would assume that any small amount of power is dissipated across the diode and the output resistor, but I'm fairly certainly for all purposes it is negligible.
 
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waqarrashid33 said:
Half wave rectifier based on the principle of PN junction diode convert either possitive or negative portion of AC current But i am confused here that when the portion of current on which the diode is reverse biased current is almost zero then where the energy of that portion goes?

The energy is only transferred when the diode is forward biased. That is why a full-wave rectifier is more efficient in energy transfer.
 
you mean the energy of current which i blocked by diode is transfred when the diode is farward biase?
 
No, the transformer supplies voltage to the diode and then a current will only flow if there is a path for it to flow in.

A diode simply stops the current from flowing in one direction and it doesn't have to go anywhere else. It just stops.

When the voltage reverses, and it is possible for the current to flow again, then it does flow.

It isn't like trying to stop a locomotive. The voltage can be stopped by a small diode if it has enough voltage rating to do it.

In fact, because it doesn't conduct any current (other than microscopic currents) in reverse , the diode does not even dissipate any power, so it doesn't get warm while it is stopping a high voltage.
A diode costing just a few cents can stop a voltage of up to 1000 volts.