Which Electronegativity Pairing is More Electronegative?

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Discussion Overview

The discussion revolves around the concept of electronegativity in the context of the compounds Br2, KBr, and HBr. Participants explore how to determine the relative electronegativity of these compounds without having specific electronegativity values, focusing on periodic table trends and conceptual understanding.

Discussion Character

  • Homework-related
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests that Br2 is the least electronegative due to equal sharing of electrons, but is uncertain about the relative electronegativities of KBr and HBr.
  • Another participant clarifies that electronegativity is a property of elements rather than bonds, proposing that the difference in electronegativities should be calculated by subtraction.
  • A participant expresses confusion about how to rank the compounds without knowing electronegativity values and questions the conceptual understanding of why HBr is less electronegative than KBr.
  • One participant attempts to provide a conceptual framework using a diagram of the periodic table, indicating that the difference in electronegativity between Br and K is greater than that between Br and H.
  • Another participant humorously notes that the electronegativity values should be memorized, implying that this knowledge is essential for understanding the topic.

Areas of Agreement / Disagreement

Participants do not reach a consensus on how to rank the electronegativities of the compounds without specific values, and there is confusion regarding the conceptual framework for understanding electronegativity differences.

Contextual Notes

Participants express uncertainty about the periodic trends and how to apply them without specific electronegativity values. There is a lack of clarity on the rules for estimating electronegativity differences.

Lori

Homework Statement



Br2, KBr, and HBr

Homework Equations


none

The Attempt at a Solution


I understand that Br2 would be least electronegative because they both equally share the electrons, but i don't understand why KBr is more electronegative than HBr. This question was on my quiz, and i wasn't given a table of the electronegatives, so i had to think about it.

Can someone explain how i could find out if one is more electronegative than the other based on the periodic table? Is there like a periodic table trend for electronegativity for bond pairs?

Thanks[/B]
 
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Looks to me like you are confused about something. Electronegativity is a property of an element, not of a bond or a substance. Perhaps what you mean is just the difference between electronegativities of the elements involved? If so, it just about subtracting them, no need to look for any explanation.
 
Borek said:
Looks to me like you are confused about something. Electronegativity is a property of an element, not of a bond or a substance. Perhaps what you mean is just the difference between electronegativities of the elements involved? If so, it just about subtracting them, no need to look for any explanation.
I think that's the case. But, it was on my pop quiz for chem and we were told to rank the pairs based on electronegativity. The problem was I didn't* get the electronegative numbers for each element.

Is there a rule to like estimate the differences? I know that Br2 is least electronegative since the difference is 0
 
Does anyone know how i can figure out the ranking without knowing the electronegativity values? Perhaps, there is something conceptually i don't know about? I'm confused on how i know the Hbr is less electronegative than Kbr
 
Lori said:
Does anyone know how i can figure out the ranking without knowing the electronegativity values? Perhaps, there is something conceptually i don't know about? I'm confused on how i know the Hbr is less electronegative than Kbr

Hey Lori! :oldsmile:

Consider that the periodic system looks like the following with electronegativity.
And note that H and K are both in group 1, and K and Br are both in period 4.

H
##\uparrow## (increasing electronegativity)
K ##\rightarrow## (increasing electronegativity) Br

From this diagram we can conclude that the difference between Br and K must be greater than the difference between Br and H.
 
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Lori said:
The problem was I didn't* get the electronegative numbers for each element.

Its chemistry, you should have learned them by heart :-)
 

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