Which Way Does the Normal Vector in da Point?

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Homework Help Overview

The discussion revolves around the interpretation of the normal vector in the context of current density and its implications for calculating current and magnetic fields using Ampère's Law. The subject area includes electromagnetism and vector calculus.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the direction of the normal vector in relation to current density and its effect on current calculations. Questions arise regarding the implications of the normal's orientation on the sign of the current. Additionally, there is a discussion about the application of Ampère's Law and whether it accounts for the entire wire or just a segment.

Discussion Status

Participants are actively engaging with the questions posed, offering differing perspectives on the direction of the normal vector and its relevance. Some guidance has been provided regarding the outward-facing normal, but there remains uncertainty about the implications of different orientations and the overall application of Ampère's Law.

Contextual Notes

There are indications of potential confusion regarding the definitions and implications of current density and magnetic field calculations. The discussion reflects a need for clarity on how these concepts interact, particularly in relation to the geometry of the system being analyzed.

Niles
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Hi all

I have two questions.

1) We have the following expression for the currect:

I = \int\limits_\mc S {{\bf{J}} \cdot {\rm{d}}{\bf{a}}}

Which way does the normalvector in da point? I think it's very crucial, because I might end up with a negative current if I don't get this right.

2) When I want to find the magnetic field a distance s from a wire, which has a current I going through it, I use Ampére's Law. But when I do this, don't I only find the magnetic field caused by a single "disk" in the wire?


Niles.
 
Last edited:
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I am pretty sure it should be the outward facing normal.
 
Yes, but there's two ends, so it might go either way?
 
Yes... If I have a cylinder that looks like

O---------O

The normal on the left side will be pointing to the left, and the normal on the right side will be pointing to the right.
 
1) depends on what you consider the direction of J.
J is always the direction of the current... So J.da=J* da* cos(theta) will depend on the angle theta

2) its like gauss law..in gauss law..no matter how many charges are present outside, Electric Field on the surface depends on the charge enclosed by the surface only, right?
Similarly here B depends on Ienclosed
 

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