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newb

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Why is acceleration always squared?

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- Thread starter newb
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In summary, Sojourner says that acceleration is rate of change of velocity, which is per second, and that you can determine how fast someone will be going given a number of seconds from now by multiplying that number (of seconds) times the 3 ms they're gaining each second.

- #1

newb

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Why is acceleration always squared?

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- #2

Integral

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It's not.

v = at + v_{0}

v = at + v

- #3

jtbell

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F = ma

[tex]x = x_0 + v_0 t + \frac{1}{2} a t^2[/tex]

[tex]x = x_0 + v_0 t + \frac{1}{2} a t^2[/tex]

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- #4

Sojourner01

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Because acceleration is rate of change of velocity. Rate of something is per second. Velocity is already metres per second - so acceleration is metres per second, per second.

- #5

LURCH

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Maybe Sojourner's response already made it clear enough, but:

Suppose I only told you I was traveling at 3meters per second. You could know the total distance I'll travel in a given number of seconds by multiplying that number of seconds by 3 (6 meters in 2 seconds; in 5 seconds, 15 meters, and so on...). So rate of speed is a matter of multiplication, and the conjunction "per" actually means "multiplied by", or "times", and "meters per second" actually means "meters x seconds".

Well, I haven't given you enough information to tell what my rate of acceleration is, have I? But, if I tell you that I was standing still a second ago, and I'm moving at three meters per second (ms) now, and then a second later I tell you that I'm going six ms, you can determine a pattern. Although I've only reported my speed (in ms), you can see that every second, I'm going three meters per second faster than I was the second before, so I'm gaining three ms each second (or "per second"). So, you can tell how fast I'll be going a given number of seconds from now by multiplying that number (of seconds) times the 3 ms I'm gaining each second (after 1 second, I was going 3ms, after 3 seconds, 9ms; at 10 seconds, I'll be going 30ms and so forth...). Hence, three "meters per second", per second, or (since "per" means "times") "meters x seconds x seconds". And, since to multiply any number times itself is to square that number, "seconds x seconds" = "seconds^{2}", so 3 mss = 3 ms^{2}.

Suppose I only told you I was traveling at 3meters per second. You could know the total distance I'll travel in a given number of seconds by multiplying that number of seconds by 3 (6 meters in 2 seconds; in 5 seconds, 15 meters, and so on...). So rate of speed is a matter of multiplication, and the conjunction "per" actually means "multiplied by", or "times", and "meters per second" actually means "meters x seconds".

Well, I haven't given you enough information to tell what my rate of acceleration is, have I? But, if I tell you that I was standing still a second ago, and I'm moving at three meters per second (ms) now, and then a second later I tell you that I'm going six ms, you can determine a pattern. Although I've only reported my speed (in ms), you can see that every second, I'm going three meters per second faster than I was the second before, so I'm gaining three ms each second (or "per second"). So, you can tell how fast I'll be going a given number of seconds from now by multiplying that number (of seconds) times the 3 ms I'm gaining each second (after 1 second, I was going 3ms, after 3 seconds, 9ms; at 10 seconds, I'll be going 30ms and so forth...). Hence, three "meters per second", per second, or (since "per" means "times") "meters x seconds x seconds". And, since to multiply any number times itself is to square that number, "seconds x seconds" = "seconds

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- #6

newb

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(1)why is acceleration m/s"squared"?

I don't understand why the "second" is "squared" why isn't the "meter" squared?

(2) If there's an object with a mass of 10kg in space and you apply 20N of force on that object, with no other influences that object will accelerate

a= 20N / 10kg = 10N/kg?

So the object would accelerate 10N/kg what does that even mean?!

And if that's suppose to mean 10m/s2 then does that mean the object will continue picking up speed forever since there's no force opposing it, or would it travel at some constant velocity?

I hope someone can understand what I'm trying to get out. Thanks.

- #7

Cyrus

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A second squared is meaningless. It is meter per second, per second, i.e. the time rate of change of velocity.

(2) Yes.

What is a Newton?

[tex] \frac {kg \cdot m}{s^2} [/tex]

Yes, it will accelerate forever.

- #8

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newb said:I'm new too physics and just learning about forces, energy,boyancy etc. but I'm having trouble understanding:

(1)why is acceleration m/s"squared"?

I don't understand why the "second" is "squared" why isn't the "meter" squared?

You have asked this question before!

Several people have responded. What did you not understand out of those responses?

I'm going to merge that thread into this one, and then move it to the Homework forum where it belongs. Please post this type of question in that forum from now on.

Zz.

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- #9

BishopUser

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- #10

newb

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Thanks for all the answers, I really appreciate it!

A "newbie" is a slang term for someone who is new or inexperienced in a particular field or activity.

People ask "newbie" questions because they are new to a particular topic and are seeking clarification or understanding.

Yes, "newbie" questions are important because they allow individuals to learn and understand a topic in a more thorough and complete manner.

To answer "newbie" questions effectively, it is important to be patient, provide clear and concise explanations, and offer additional resources for further learning.

No, it is never too late to ask a "newbie" question. It is always better to seek understanding and clarification, even if it may seem late, rather than remaining confused or misinformed.

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