Why are current sources replaced with open circuits in Thévenin equivalent analysis?

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gfd43tg
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Hello,

For thévenin equivalent circuits, I thought current sources are replaced with open circuits and voltage sources are replaced with short circuits.

In this video, the guy replaces both with open circuits, so I am not understanding how that works.


Because of all the different methods I am seeing for solving for Vth, I cannot figure out what to do because I am being bombarded with too many techniques.
 
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The video author is treating the voltage source as the load of the circuit so it is not strictly part of the circuit under consideration. Therefore he treats it like a load and open-circuits it.

I know this stuff is confusing. Small wonder Circuits is usually the least favorite class of Engineering majors!