Why Are Initial Conditions x(0) and v(0) Preferred Over a(0) in ODE Solutions?

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SUMMARY

The discussion centers on the preference for initial conditions of position x(0) and velocity v(0) over acceleration a(0) in solving ordinary differential equations (ODEs) related to oscillatory motion. Specifically, the ODE in question is \(\ddot{x}+2{\gamma}\dot{x}+{{{\omega}_0}^2}x=0\). The consensus is that acceleration is inherently determined by the system's properties, such as the spring constant, once the initial position is set. Therefore, specifying initial conditions for position and velocity provides a more direct and practical approach to solving the ODE.

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littleHilbert
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Hi, World! Nice place here! My first post in this forum. :smile:

I've got a short question for a start.
If we wish to evaluate the constants for the general solution
x(t)=C_1e^{-{\lambda_1}t}+C_2e^{-{\lambda_2}t}
of this ODE:
\ddot{x}+2{\gamma}\dot{x}+{{{\omega}_0}^2}x=0
we can choose the initial conditions: x(0)=x_0,\dot{x}(0)=v_0
I cannot see at a glance why we can't choose an initial condition of acceleration and try to calculate the constants using this value. Why do we choose x_0,v_0 and not for example x_0,a_0 with a_0={{\lambda_1}^2}C_1+{{\lambda_2}^2}C_2?
 
Last edited:
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Hey, Guys...why silence?
Did I ask nonsense? :rolleyes:
I don't think it's nonsense.
In the meantime I came across some info on oscillations in Feynman's lectures.
It says we cannot specify acceleration with which the motion started because it is determined by the spring, once we specify x_0. But isn't the velocity also dependent on the properties of the spring then?
 

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