Why body A has greater acceleration?

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Homework Help Overview

The discussion revolves around the acceleration of two bodies, A and B, in a physics problem involving forces, mass, and tension in a system with a pulley. The context includes assumptions about massless components and a frictionless surface, with a specific gravitational acceleration given.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between mass, force, and acceleration, questioning the implications of the tension in the string and the connection between the masses. There are attempts to clarify the role of the 1 kg mass and its effect on the system's dynamics.

Discussion Status

The discussion is ongoing, with participants offering different perspectives on the forces at play and the connections between the bodies. Some suggest using free body diagrams to better understand the forces involved, while others express confusion about their previous understanding of similar problems.

Contextual Notes

There is mention of assumptions regarding the mass of the pulley and string, as well as the frictionless nature of the table surface. Participants also reflect on their prior experiences with similar problems and the potential for forgetting concepts after a break from study.

Iamconfused123
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Homework Statement
question is which body A has greater acceleration?
Relevant Equations
F=ma
Apparently body A has greater acceleration and I don't get why. Can someone please explain.

It's stated to take g=10/s^2.
Both bodies have same mass.
Nothing about rope elasticity is added, and nothing about the pulley. So I assumed they are both massless, and no friction between them.
Also, the table surface is frictionless.
Thank you
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The pulley and string may be massless, but the 1 kg mass is definitely not massless!
 
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yeah but, 1kg×10m/s^2=10N so both forces are the same, masses the same, thus accelerations are the same
 
Iamconfused123 said:
yeah but, 1kg×10m/s^2=10N so both forces are the same, masses the same, thus accelerations are the same
No, they are not. If the tension in the string were 10 N then the net force on the 1 kg mass would be zero and it would not accelerate.
 
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Iamconfused123 said:
yeah but, 1kg×10m/s^2=10N so both forces are the same, masses the same, thus accelerations are the same
Yeah but, the 1 kg mass is not massless.
 
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Orodruin said:
No, they are not. If the tension in the string were 10 N then the net force on the 1 kg mass would be zero and it would not accelerate.
But the bodies(A and B) are not connected, if that is what you are saying.
 
Iamconfused123 said:
But the bodies(A and B) are not connected, if that is what you are saying.
The 1kg mass is connected to B.
 
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PeroK said:
The 1kg mass is connected to B.
Okay, but why does that matter? 1kg is falling with 10N pulling B with 10 N, same force as the hand is pulling A
 
Iamconfused123 said:
Okay, but why does that matter?
It;s fundamental.
Iamconfused123 said:
1kg is falling with 10N
What does that mean?
Iamconfused123 said:
pulling B with 10 N, same force as the hand is pulling A
Is it? What about Newton's third law? If the 1 kg mass pulls B with a force of 10N, then B pulls the 1kg mass with an opposite force of 10N, and the 1kg won't move, as it has a zero net force acting on it.
 
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  • #10
May I suggest drawing free body diagrams of each mass ( A,B, and 1kg) for us to examine together?
 
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  • #11
ohh. I figured. How stupid am I :headbang::headbang::headbang::headbang::headbang:
 
  • #12
Thanks everyone. :bow:
 
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  • #13
erobz said:
May I suggest drawing free body diagrams of each mass ( A,B, and 1kg) for us to examine together?
Like, I never draw those. And the best thing is that I have solved whole bunch of problems with like these, but they were like, calculate acceleration. I did take a brake from physics for 2 weeks or so, but still, like I knew how to do these problems. Is it normal for people to forget that fast?
 
  • #14
Iamconfused123 said:
ohh. I figured. How stupid am I :headbang::headbang::headbang::headbang::headbang:
It's not that big a deal. It's tricky like that on purpose. Thats why its important to draw a FBD, because it becomes apparent when to "see" the forces.
 
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