Why Might the Square of a Sum Not Equal the Sum of Squares for Matrices?

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The square of a sum for matrices, expressed as (e+f)², does not equal the sum of squares due to the non-commutative nature of matrix multiplication. The correct expansion is (e+f)(e+f) = e² + ef + fe + f², highlighting that the terms ef and fe are distinct. This distinction arises because, in matrix operations, the order of multiplication matters. The discussion emphasizes the importance of recognizing these properties when working with matrices of any size. Understanding this concept is crucial for accurate matrix calculations.
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(e+f)^2 = e^2+2ef+f^2
Why is this not neccesary true for squares matrices for all size?
 
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(e+ f)^2= (e+f)(e+f)= e^2+ fe+ef+ fe. Remember that multiplication of matrices is not, in general, commutative!
 
HallsofIvy said:
(e+ f)^2= (e+f)(e+f)= e^2+ fe+ef+ fe. Remember that multiplication of matrices is not, in general, commutative!
Do you mean (e+f)2 = e2+fe+ef+f2? I might be misinterpreting it but I can't see where that extra "fe" came from and where the "f2" went.
 
Yeah, that's what he meant: (e+f)² = e² + ef + fe + f².
 
One of these days, I'm going to learn to type!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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