Why Can't We Get Inside a Wall?

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SUMMARY

The discussion centers on the inability of fermions, such as electrons, protons, and neutrons, to penetrate solid walls due to the Pauli Exclusion Principle, which prohibits identical fermions from occupying the same quantum state. In contrast, photons, which are bosons, can interact with materials like glass but cannot penetrate walls due to insufficient energy levels as described by the equation E = hc/(wavelength). The conversation also highlights that while visible light cannot pass through walls, gamma rays can, and the absorption coefficients of materials vary with wavelength, necessitating experimental determination.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the Pauli Exclusion Principle
  • Knowledge of particle physics, including the distinction between fermions and bosons
  • Familiarity with the equation E = hc/(wavelength) and its implications
  • Basic comprehension of the Beer-Lambert law and its application in absorption studies
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  • Research the implications of the Pauli Exclusion Principle in quantum mechanics
  • Explore the properties of bosons and fermions in particle physics
  • Study the Beer-Lambert law in detail and its applications in material science
  • Investigate the interaction of different wavelengths of electromagnetic radiation with various materials
USEFUL FOR

Students and professionals in physics, particularly those interested in quantum mechanics, particle physics, and material science, will benefit from this discussion.

Neelesh
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Get into the wall !

I want to say that we can't go into the wall b'cus we know that we are made up of atoms (mainly electrons, protons and neutrons) and all these are fermions, and so as wall. Since fermions follow Pauli's Exclusion Principle. Suppose, we get inside the wall so the fermions (electrons, protons and neutrons) occupy the same quantum state and that is the violation Pauli's Exclusion Principle. So, this implies that we can't enter inside the wall.

Now, photons can enter inside the glass slab but not inside a wall (both are solids)?
Answer is that since photons are bosons(don't obey Pauli's Exclusion Principle) so, when they enter inside the glass the interact with fermions which is not the violation of Pauli's Exclusion Principle. But, the photons of visible light don't have sufficient energy according to equation-

E = hc/(wavelength)

So, it can't pass through wall but instead a gamma ray is taken (havin' wavelength > wavelength of visible light, can enter inside a wall.

So, is this proposition true?
 
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Neelesh said:
So, is this proposition true?
No. Here's a counter-example: water is highly transparent at visible energies (~10^15 Hz) but highly opaque at about 10 times higher energies (~10^16 Hz) and 10 times lower energies (~10^14 Hz).

Ref: See fig 7.9, p 315, J. D. Jackson, Classical Electrodynamics (3 Ed.)
 
Neelesh said:
... the photons of visible light don't have sufficient energy according to equation-

E = hc/(wavelength)

So, it can't pass through wall but instead a gamma ray is taken (havin' wavelength > wavelength of visible light, can enter inside a wall.

Radio waves have energy far less than that of visible light and yet they do get through the wall.:rolleyes:

The reason is:
Coefficients of absorption vary both with type of material and specific wavelength, the value of which must usually be determined by experiment.

However...
For any particular material and wavelength, the absorbance varies with concentration of the absorbing material, the length of material the light passes through, and the coefficient of absorption.

Here, have a Beer:
http://en.wikipedia.org/wiki/Beer-Lambert_law

Creator:biggrin:
 
Last edited:

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