Undergrad Why can't we use negative values of n in the 1D particle in a box system?

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In the 1D particle in a box system, negative integer values of n are not used because they imply a negative wavelength, leading to contradictions in the derivation. The quantization condition arises from the wave function needing to be zero at the boundaries, which restricts n to positive integers. The energy states are proportional to n^2, making the distinction between ±n irrelevant for measurable quantities. Although mathematically substituting n = -2 for n = +2 does not change the probability distribution, it does not align with the physical interpretation of the system. Thus, only positive integer values of n are valid in this quantum mechanical model.
Thejas15101998
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In the 1D particle in a box system why don't we take negative integer values of n besides the positive integer values? Well I thought about it and I think the reason is that during derivation we get ka=n (wavelength ) and thus n being negative implies that wavelength is negative hence contradiction.
 
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Thejas15101998 said:
I think the reason is that during derivation we get ka=n (wavelength ) and thus n being negative implies that wavelength is negative hence contradiction.

what is n?
Iis it related to k= n.pi/L or n.pi/a if a is the width of the box
moreover this condition is due to the acceptable wave function (solution of the Schrodinger equation) being zero at the boundary
i.e. at x=0 and x=a

and which dynamical variable is being quantised ?
Is it energy state ?
and if its energy ,then it may be proportional to n^2 rather than n.
 
Quantum states are uniquely defined up to a complex phase factor. What difference is there between ±n?
 
Thejas15101998 said:
In the 1D particle in a box system why don't we take negative integer values of n besides the positive integer values?
How does the wave function change for e.g. the second eigenstate if you replace n = +2 with n = -2? Does this make any difference in physically measurable quantities?
 
Here we are considering the time independent Schrödinger equation.
 
This may not make any difference in the physically measurable that is probability.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA

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