Why do 2 d not decay into alpha particle and neutral pion?

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SUMMARY

The decay reaction dd → απ0, where α represents the Helium-4 nucleus and d denotes the deuteron, has never been observed due to the violation of conservation of mass. The combined mass of the decay products (3862.27 MeV) exceeds the initial mass of the two deuterons (3751.2 MeV), indicating that mass conservation is not upheld in this reaction. While energy is conserved, the reaction cannot occur under normal conditions as it contradicts fundamental conservation laws.

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MxwllsPersuasns
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Homework Statement



The reaction dd → απ0 (where α is the Helium-4 nucleus and d denotes the deuteron) has never been observed. Why?

Homework Equations

The Attempt at a Solution


[/B]
So I checked first the masses to make sure energy/momentum are conserved and found out that mass of 2d is 3751.2 MeV while the decay products have a combined mass of 3862.27 which is greater than the initial state and thus violates conservation of mass. Could this possibly be the case? It just seems simple and we're currently studying topics such as isospin and parity and so I had checked things like charge and baryon number conservation and they seemed alright so I figured I might ask here. Thanks guys!
 
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MxwllsPersuasns said:
and thus violates conservation of mass
Mass is not conserved. Energy is conserved but you could collide two particles with enough kinetic energy to make heavier particles. This is what particle colliders do.
 

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