Why Do Atoms (generally) Follow The Octet Rule?

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SUMMARY

Atoms generally seek to fill their electron shells to achieve stability, primarily due to the presence of eight low-energy states for electrons, which is derived from solutions to the Schrödinger equation for hydrogen-like atoms. The octet rule, while often seen as a guideline, is influenced by the Pauli Exclusion Principle (PEP), which is essential for understanding atomic structure and stability. The PEP, often treated as an additional assumption in basic quantum mechanics, is crucial for the existence of atoms as we know them. A more thorough introduction to the relativistic treatment of quantum mechanics could enhance the understanding of these fundamental concepts.

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  • Understanding of the Schrödinger equation in quantum mechanics
  • Familiarity with the Pauli Exclusion Principle (PEP)
  • Knowledge of electron orbital configurations
  • Basic concepts of relativistic quantum mechanics
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  • Explore the relativistic treatment of the Schrödinger equation
  • Learn about electron orbital energy levels and their configurations
  • Investigate exceptions to the octet rule in various elements
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I understand that there are a lot of exceptions to the octet rule, but why do atoms generally WANT to be filled up with electrons?

I asked my chemistry friend about this, he didn't have an answer, so I'm assuming that there is a fundamental answer somewhere in QM.
 
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There are more exceptions than atoms following this rule.
Those atoms have (apart from filled shells) 8 low-energy states for electrons, so they "like" to fill them with electrons. That number of 8 comes from the solution of the Schroedinger equation for hydrogen-like atoms, with some modifications to account for other electrons.
 
Actually, if I understand correctly, the standard Schrödinger equation does not account for the octet rule, since the filling of shells requires the Pauli Exclusion principle (PEP) as well. The PEP is usually treated as an ad hoc extra assumption in basic chemistry QM, whereas in fact it falls directly out of a relativistic treatment, something Schrödinger himself did not do (or did he?). In my opinion this should be treated as more important in basic QM than it typically is, since without the PEP there would be no atoms as we know them, hence no matter and no chemistry (or very different chemistry). The fact that the math of the relativistic solution is hard should not preclude at least an introductory presentation in intro physchem.
 
Those are the modifications to account for other electrons - you have to fill other orbitals, and their energy gets modified (in particular, s-orbitals are below p-orbitals and those are below d-orbitals with the same principal quantum number).
 
So, you're saying that the reason that 8 is sometimes favored by hydrogen like atoms, is answered by Schrödingers equations?
 
Depends on the interpretation of "answered".
If you look for total antisymmetric solutions for n electrons around a nucleus (satisfying the Schrödinger equation), you get energy levels where you can see that number of 8 with the correct interpretation. This is a messy way to calculate energy levels, however.
 
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