Why Do Closed Pipes Not Produce Even Numbered Harmonics?

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SUMMARY

Closed pipes cannot produce even-numbered harmonics due to their physical structure, which requires a pressure node at the closed end and a pressure antinode at the open end. This configuration allows only odd harmonics, with the first overtone being three times the fundamental frequency. The absence of even harmonics is confirmed by the relationship that even harmonics cannot satisfy the condition of having a closed end at an even integer multiple of the wavelength. Understanding this principle is crucial for A-level physics students.

PREREQUISITES
  • Understanding of wave mechanics and harmonic frequencies
  • Familiarity with the concepts of pressure nodes and antinodes
  • Basic knowledge of the relationship between wavelength and length of pipes
  • Experience with calculating frequencies and wavelengths in physics
NEXT STEPS
  • Study the principles of standing waves in closed and open pipes
  • Learn about the mathematical derivation of harmonics in different types of pipes
  • Explore the concept of resonance and its applications in musical instruments
  • Investigate the physical implications of pressure nodes and antinodes in fluid dynamics
USEFUL FOR

A-level physics students, educators teaching wave mechanics, and anyone interested in the acoustics of musical instruments.

nina
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Why can't closed pipes produce even numbered harmonics? I have been given an explanation, but it isn't very detailed. I'm doing A2 (or just A level) physics, so an explanation suitable for this level would be greatly appreciated!
Thanks.
 
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What explanation have been given to you so far
 
Just that the 1st overtone has a frequency of 3 times the fundamental frequency, therefore the second harmonic is missing.

Is that all I need to know? It doesn't seem much of an explanation to give in an exam.

Thanks for your help...
 
yup it not enough Can u calulate the wavelength in terms of L
 
Yes, I can calculate the wavelength from L. But why is there no second harmonic in a closed pipe?
 
Coz for Even harmonics u need a arrangement like this
2f, 4f which is clearly not possible

And u never get L = even integer * Wavelength
 
Thanks! I will look at that more closely. thanks for the link too.:smile:
 
basically it is due to the fact that there is pressure antinode and node at closed and open ends
 
  • #10
actually, it makes sense now.
thank you so much. i may just get a good grade in my exam now...
:smile:
 
  • #11
Goodluck for exams
 

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