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**Why do I get a different answer with the parallel axis theorem? [Solved]**

## Homework Statement

Imagine four points masses m1 = m3 = 3kg and m2 = m4 = 4 kg. They lie in the xy plane with m1 at the origin, m3 at (0, 2), m2 at (2, 2), and m4 and (2, 0). Each unit on the coordinate plane corresponds to a distance of one meter. What is rotational inertia of the system about the z-axis?

## Homework Equations

Rotational inertia = sum of component inertias

inertia for a point mass = m*r^2

parallel axis theorem: rotational inertia around new axis = old rotational inertia + mass of system * (distance of new axis from old axis)^2

## The Attempt at a Solution

Because m1 is located on the axis of rotation, I ignore it.

inertia of m3 = 3kg * (2m)^2 = 12kg * m^2

distance of m2 from z-axis = sqrt((2m)^2 + (2m)^2) = 2sqrt(2)m

inertia of m2 = 4kg * (2sqrt(2)m)^2 = 32kg * m^2

inertia of m4 = 4kg * (2m)^2 = 16kg * m^2

total = 60kg*m^2

This seemed to be fine, but my book gave me an answer of 56 (with no explanation). Just for kicks, I decided to calculate the rotational inertia of the system around an axis in the center of the four masses (the line defined by x = y = 1).

Then, the masses are all equidistant from the axis with a radius of sqrt(2)m.

So the rotational inertia (through the new axis) would be (3kg + 3kg + 4kg + 4kg) * (sqrt(2)m)^2, or 28kg*m^2.

Then, I used the parallel axis theorem to find the rotational inertia of the system through the z-axis.

new rotational inertia = 28kg*m^2 + (sqrt(2)m)^2*28kg = 56kg

Can anyone see what I'm doing wrong?

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