Why Do Ligands Donate Electrons to Electropositive Transition Metals?

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SUMMARY

Ligands such as ammonia, chlorine, and oxygen donate electrons to electropositive transition metals due to the nature of ionic and covalent bonding rather than electronegativity alone. When ligands interact with transition metals like Cr3+ or Cu2+, the attraction between positively charged metal ions and negatively charged or polar ligands is driven by Coulombic forces. This interaction is not hindered by the electronegativity of the ligands, as the bonding occurs after the formation of ions, where the electron density around the ligands allows for electron donation despite their electronegative character.

PREREQUISITES
  • Understanding of ionic and covalent bonding principles
  • Familiarity with transition metals and their oxidation states
  • Knowledge of Coulombic forces in chemistry
  • Basic grasp of electronegativity and its scales (Pauling and Mulliken)
NEXT STEPS
  • Study ligand field theory to understand complex bonding in transition metals
  • Research the Pauling and Mulliken scales of electronegativity for deeper insights
  • Explore the role of electron density in polar molecules like water
  • Investigate the properties and behaviors of common transition metal complexes
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Chemistry students, educators, and professionals interested in coordination chemistry and the behavior of transition metals in complex formation.

hariharan venkatasu
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TL;DR
Transition metal/ligands interaction
Transition metals, being metals, are electropositive.Ligands like ammonia,oxygen,chlorine etc ,on the other hand,are mostly electronegative(electron loving).How come the Ligands donate electrons to the electro positive(electron hating)transition metals when both have contradictory characteristics. Could you please clear my confusion?​
 
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Try starting with just the introduction (before the Table of Contents) here:
https://en.wikipedia.org/wiki/Electronegativity

Then go on to:
https://www.khanacademy.org/science...onds-and-reactions/v/electronegativity-trends

and the one that immediately, and automatically, follows it:
https://www.khanacademy.org/science...ctions/v/electronegativity-and-chemical-bonds

And perhaps read more of the Wikipedia article if you are interested. It gives some background too.

If you need to go further, we can probably get some chemistry folks here to jump in.

Cheers,
Tom
 
Thank you for your prompt reply.My question was how can a ligands like ammonia, chlorine,oxygen etc donate electron to a transition metal?These ligands are elctronegative in character and are reluctant to part with their electrons.More over transition metals, being metals are electropositive,and will be unwilling to accept electrons.They prefer to part with their valence electrons.How this anomaly could be explained?
 
hariharan venkatasu said:
how can a ligands like ammonia, chlorine,oxygen etc donate electron to a transition metal?

Under what circumstances does this happen? Can you give more specifics?
 
Put complexes aside for a moment. Let's try with something simpler. Imagine you have a water molecule. Oxygen is highly electronegative, so it attracts electrons - yet it has two free electron pairs, that it can - despite hydrogen being way more electropositive, even comparable with Mo - donate to a proton and create a hydrogen bond (or even just a bond like in hydronium). Why is is it so? Well, first - these electron pairs despite being attracted to the oxygen still have large density of excess electrons, second - electronegativity is a property of an element, when it comes to ions it has to be treated with caution, H+ - having a positive charge - attracts electrons much more than the hydrogen electronegativity would suggest.

When it comes to complexes things are being complicated by other factors (see ligand field theory or crystal field theory for example), but you are still having cation and electron pairs, so at some level similar factors are at work.
 
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Thanks a lot for the enlightening answer.But why a reference to Mo is made?
 
Only because being transition metal it has particularly high electronegativity, comparable with that of hydrogen.
 
Thanks a lot for clarification
 
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This is a good question. Let's review electronegativity.

There are several ways the value is defined, but the most common ones you see is the Pauling scale. The equation is given as the absolute difference of electronegativity between two atoms A and B:
|\chi_{\rm A} - \chi_{\rm B}| = ({\rm eV})^{-1/2} \sqrt{E_{\rm d}({\rm AB}) - \frac{E_{\rm d}({\rm AA}) + E_{\rm d}({\rm BB})} 2}\chi_{\rm A} and \chi_{\rm B} are the "absolute" electronegativity, E_{\rm d}({\rm AB}), E_{\rm d}({\rm AA}), and E_{\rm d}({\rm BB}) are the bond-dissociation energy of compound AB, AA, and BB. Thus, you can see from this that the electronegativity in the Pauling scale is a relative measure of electronegativity compared to hydrogen atom in a compound with hydrogen (HF, LiH, etc.). The reason why hydrogen was chosen is because they form covalent bonds with most elements. The electronegativity for hydrogen is defined as 2.20. So the values for other elements are relative to that value.

The other scale is the Mulliken Electronegativity. This is given by the following formula:
\chi = \frac{E_{\rm i} + E_{\rm ea}} 2 \where E_{\rm i} and E_{\rm ea} are the ionization energy (energy released when one electron is removed) and electron affinity (energy released when one electron is acquired) of an neutral atom. This value is a lot different from the Pauling electronegativity (it even has the unit of energy!), but it's not a relative measure.So, what does these mean?

It means that electronegativity is the property of an neutral atom in respect to how they are expected to behave once a covalent bond is formed with another atom. So the OP's question stems from the confusion that the electronegativity comes into play before a bond is formed, as opposed to the reality that they come into play after a bond is formed. When an electropositive neutral atom A and an electronegative neutral atom B forms a bond, the electrons are more dense around atom B and sparse around atom A. But this is about neutral atoms as reactants, not about ions or compounds as reactants.

So let's talk about metal ion and ligands.

For example, let's say that you have Cr3+ and three Cl- atom. At this point, the "electronegativity" is irrelevant here because they are already an ion. At this point, Cr3+ is positively charged, and Cl- is negatively charged. Positive and negative attract each other by Coulombic force, thereby forming CrCl3.

Another example, let's say that you have Cu2+ and six H2O molecules. Once again, the "electronegativity" is irrelevant here because one is an ion, and the other is a compound (not neutral atom). Once again, Cu2+ is positively charged, and the H2O molecules is polar and the electron is more dense around the oxygen atom (the lone pair electrons), although the molecule itself is neutral. Positive and negative attract each other by Coulombic force, thereby forming [Cu(H3O)6]2+.

Most people make the similar mistake by understanding it like OP did, and believe that electronegativity is what forms a bond. Electronegativity explains polarity in compounds and the bond affinity (ionic vs covalent), but it's not what causes the bond (it is indirectly related though).
 
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