Why do \pi\^{\pm} have different charges than \pi\^{0}?

[Dahaka14]

How is it that $$\pi\^{\pm}$$ have charges $$\pm e$$ and $$\pi\^{0}$$ has a charge of 0? The $$\pi\^{+}$$ has one up quark and an anti-down quark, which doesn't add up to zero (same deal goes for $$\pi\^{-}$$, and the $$\pi\^{0}$$ has a linear combination that doesn't seem to add up to zero.

Where have I gone wrong?

 

[malawi_glenn]

pi + has as you say, one up and one anti-down which gives you +2/3 + 1/3 = 1

You are saying (The $$\pi ^+$$
has one up quark and an anti-down quark, which doesn't add up to zero ) But the pi + should have CHARGE = 1e! As you said in the sentence before this one.

Maybe try to be more consistent to yourself.. try again.