Why does 1/[n log(n)]^1.1 converge

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SUMMARY

The series 1/[n log(n)]^1.1 converges, as established through the integral test. The discussion highlights that for n > 10, log(n) > 1, allowing the comparison of the series to 1/(n^1.1). This comparison demonstrates that the series converges since 1/(n^1.1) is a p-series with p = 1.1, which is greater than 1, confirming convergence.

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Homework Statement


Prove that the series:
1/[n log(n)]^1.1 converges

Homework Equations




The Attempt at a Solution




We know that nlogn is equal to d[log(log(n))] and use the integral test to show that it diverges.
However, I have no idea how to deal with the 1.1th power.
 
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n > 10

log(n) >1

Thus,

1/[(nlog(n))^(1.1)] < 1/ (n^1.1)
 

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