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Why does a ball rebounds more over the edges?

  1. Oct 3, 2012 #1
    I need an explanation for this demo.
    When a ball falls on a table, it rebounds to a certain height,, but when it falls on the edge of the same table, it rebounds to a much greater height.. What are the factors responsible for the re-bounce?
    How does area of impact effect it?
  2. jcsd
  3. Oct 3, 2012 #2
    If the table and the ball were rigid bodies, bounce would be the same. In this case, I suspect that the middle of your table has less stiffness and more ability to absorb energy. Another table may behave differently.
  4. Oct 4, 2012 #3

    Andy Resnick

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    Does it actually bounce to a greater height?
  5. Oct 4, 2012 #4


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    That occurred to me, too. It may go shooting off to the side but not actually get any higher. More description of the actual experiment is needed for a good (suggested) answer. Did you try it on concrete?
  6. Oct 4, 2012 #5
    Just establishing what I anticipate to be an enriching opportunity in tenure of the scientifically literate cognoscenti. (This is my first post in this entire forums.) xD

    Bearing in mind that I do not specialize in any means of physics, I suppose I may qualify for the approval of various hypotheses of which have so happened to randomly wander past the reactionary consciousness of my brain to the general community at hand.

    Assuming that you were speaking specifically in terms of distance per the trajectory of the ball as apart from angle, velocity, height etc., I would postulate that the ball travels further simply owing to the fact that the exertion of gravity has less of a hold on parabolic arcs whereas the pull of gravity is potentially maximized whence the ball strikes perpendicular along a surface parallel to the ground. To provide a schematic reference, perhaps you should consider the analogy of a triangular array so fashioned as to acknowledge the coherence of physical transmogrification of the comprehensibility pertaining to the whole of science. Applying the concept of a right-angled triangle, the ball, as reciprocated from the edge of contact, would traverse greater distance along the hypotenuse than any other side, eschewing the complexification of transitioning states along with any other changing factors indifferent to the element of gravitational mediation. The force of gravity is constant, but the ball still ventures further out when it rebounds at an angle than if it were simply to ricochet orthogonally on the plane of reception.

    Again, hello everyone (in the name of science).
  7. Oct 4, 2012 #6
    Its the pressure that did the job. Bouncing on a flat surface gives an equal stress on the ball. When you did it on the edges, you give a higher stress on a particular point. the ball get compressed more than on a flat surface, more energy is gained. For you information, you get the greatest bounce when the edge hits the ball at right angle at the middle of the ball :) .
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