- #1
SHO-NUFF
- 3
- 0
So I've seen all over the internet about the efficiency of a bouncy ball and how high will it bounce on the 2nd, 3rd, 4th, etc. bounces? That's easy to figure out. Now I was thinking about it for a while and the question that hit me was how much energy do I need to add to the initial drop in order for the ball to return to the exact original height? I have a table that's 1.03 m high, the ball has a mass of 7.362 g and a density of 0.90 g/cm^3. The ball is bouncing off a concrete floor that, from what I can find, has a density of 2,400 kg/cm^3. The ball also take approximately 0.5 seconds to fall and impact the floor and approximately another 0.25 seconds to reach the height of the first bounce of about 0.835 m.
I'm not sure if all this information is all relevant but it's what I've observed by simply bouncing the ball a couple dozen times. Please someone help point me in the right direction here. Again, what I'm looking for is the amount of energy required to be added in order for the ball to return to the exact original drop height on the first bounce. I'm missing something, overthinking it, or both.
I'm not sure if all this information is all relevant but it's what I've observed by simply bouncing the ball a couple dozen times. Please someone help point me in the right direction here. Again, what I'm looking for is the amount of energy required to be added in order for the ball to return to the exact original drop height on the first bounce. I'm missing something, overthinking it, or both.