1. The problem statement, all variables and given/known data Explain why a capacitor will discharge, although very slowly when there is high internal resistance? 2. Relevant equations V=IR Q=V/C 3. The attempt at a solution I am confused slightly by internal resistnace. Does that refer to regular resistance. From that high internal resistance results in large resistance therefore large p.d. therefore from Q=V/C V=QC so large voltage means that there will be large capacitance?