lavster Messages 213 Reaction score 0 Thread starter Dec 8, 2013 #1 why does a change in impedance causes reflection? I know that R=(Z2-Z1)/(Z1+Z2), but what is it that makes the wave be reflected? thanks
why does a change in impedance causes reflection? I know that R=(Z2-Z1)/(Z1+Z2), but what is it that makes the wave be reflected? thanks
Dale Mentor Insights Author Messages 37,019 Reaction score 16,030 Dec 8, 2013 #2 Basically it comes from energy conservation. At an interface of difference impedances not all of the energy will be transmitted beyond the interface. Since energy must be conserved, whatever is not transmitted must be reflected.
Basically it comes from energy conservation. At an interface of difference impedances not all of the energy will be transmitted beyond the interface. Since energy must be conserved, whatever is not transmitted must be reflected.
Claude Bile Science Advisor Messages 1,478 Reaction score 26 Dec 13, 2013 #3 An alternate, but equivalent explanation to Dale's, is that reflection occurs so as to satisfy the boundary conditions at the interface. Claude.
An alternate, but equivalent explanation to Dale's, is that reflection occurs so as to satisfy the boundary conditions at the interface. Claude.