Why Does Calculating Runner A's Distance Give Different Results?

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Homework Help Overview

The discussion revolves around calculating the distance covered by Runner A, who runs at a constant speed of 6.0 m/s for a duration of 10 seconds. The original poster expresses confusion about how the distance of 60 meters is derived from the given information.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants question how to derive distance from velocity and time, emphasizing the relationship between units. There is also a mention of using a distance formula, but clarity on its application is sought.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between velocity, time, and distance. Some guidance on unit analysis has been provided, but there is no consensus on the method to arrive at the solution.

Contextual Notes

The original poster has provided a set of equations related to motion, but there may be confusion regarding their application in this specific scenario. The discussion reflects a need for clarification on the fundamental concepts involved.

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Homework Statement


Runner A runs at 6.0 m/s for 10 s. How far does he go?
NOTE: THE ANSWER IS 60 m BUT I DON'T KNOW HOW IT GOT TO THAT.

Homework Equations


V=Vo + at
X=1/2(Vo +V)T
X=volt + 1/2at2
V2=Vo2 + 2ax

(If a 2 is after a letter then it means squared)
X=displacement
A=Acceleration
T=Tome
Vo=Initial Velocity
V=Velocity


The Attempt at a Solution



X=1/2(Vo +V)T
x=1/2(6 m/s)(10 sec)
 
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You have a velocity (m/s) and a time (s). Even just looking at the units, how would you get a distance (m) ?
 
fss said:
You have a velocity (m/s) and a time (s). Even just looking at the units, how would you get a distance (m) ?

You get the distance using the distance formula that I have listed above under previous tries...
 
lol poor attempt at trolling tbh.
 

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