Why Does Including the Zero Vector Make a Set Linearly Dependent?

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Homework Help Overview

The discussion revolves around the concept of linear dependence in vector spaces, specifically focusing on the implications of including the zero vector in a collection of vectors. Participants are exploring the definitions and properties related to linear dependence and the role of the zero vector in such contexts.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants are attempting to understand the definition of linear dependence and how the inclusion of the zero vector affects it. Questions are raised about the implications of expressing vectors as linear combinations and the specific phrasing of the problem regarding the zero vector.

Discussion Status

Some participants have provided insights into proving that a set containing only the zero vector is linearly dependent, while others are exploring related problems about linear dependence involving additional vectors. There is an ongoing exchange of ideas, with some guidance offered on how to approach the proofs, but no consensus has been reached on the broader implications yet.

Contextual Notes

Participants are navigating the definitions and properties of linear dependence, with some confusion noted regarding the phrasing of the original problem. The discussion includes attempts to clarify the requirements for proving linear dependence in various scenarios.

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Homework Statement


Prove that any collection of vectors which includes [tex]\theta[/tex] (zero vector or null vector)is linearly dependent. Thus, null vector cannot be contained in a basis.


The Attempt at a Solution


Well, I know that in order for a collection of vectors to to be linearly dependent, one vector can be expressed as a linear combination of other vectors such as:
let s be some non-zero scalar
let v be vectors

s1v1 + s2v2 + ... + skvk = 0

but let's say that v2 was a zero vector (is this what the question is asking?),
-s2v2 = s1v1 + s3v3 + ... + skvk?
I don't quite get the phrase "any collection of vectors which includes 0(theta)"
 
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Start off by proving the set containing ONLY the zero vector is linearly dependent. It's easiest to use the direct definition here: A set of vectors v1,..., vn is linearly dependent if and only if there exist coefficients s1,..., sn such that not all the si are zero (but some of them are allowed to be) and that

s1v1 + ... + snvn = 0

If you only have the zero vector, what s1 can you pick to satisfy this? Then consider if you add additional vectors... what coefficients can you pick for them?
 
Okay thanks, I got that one. How about this one?

1. Homework Statement
Prove that if the vectors b1, b2,...bm are linearly dependent, then any collection of vectors which contains the b's must also be linearly dependent

3. The Attempt at a Solution
So to be linearly dependent,
s1b1 + s2b2 +... + smbm = 0
given that the scalar s is not equal to zero.

How should I go about proving this one?
 
dracolnyte said:
Okay thanks, I got that one. How about this one?

1. Homework Statement
Prove that if the vectors b1, b2,...bm are linearly dependent, then any collection of vectors which contains the b's must also be linearly dependent

3. The Attempt at a Solution
So to be linearly dependent,
s1b1 + s2b2 +... + smbm = 0
given that the scalar s is not equal to zero.
There is NO "scalar s" in what you wrote! You mean that "at least one of the s1, s2, ..., sm is not 0."

How should I go about proving this one?
If a collection of vectors includes the b's, take the coefficients of the addtional vector to all be 0.
 

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