Why does it keep getting harder to break a pencil in 2?

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SUMMARY

Breaking a pencil in two becomes increasingly difficult due to the mechanics of torque and surface area. As the pencil is broken, the length of the remaining fragments decreases, which reduces the effective distance from the pivot point, thereby increasing the force required to apply the same torque. The discussion highlights that when the pencil is held in hand, the force needed to break it doubles with each attempt due to the reduction in surface area and the resultant decrease in torque. A fixed position, such as using eye hole screws, allows for consistent force application without the same increase in difficulty.

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Consider a pencil. Now break it in 2. Do it again and it s obvious it gets harder to do it. Why is that?
I thought of modeling the problems as a hinged beam with moments applied at both ends having opposite directions and same torque. So basically the length of the beam doesn't affect the moment diagram which constant and equal to the moments. As the beam length change we will still have the same moment distribution so why does it get harder? And what's the reason it breaks near the middle? Thank you.
 
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It's not clear to me just how you are holding this pencil. Perhaps you could post a diagram?
 
Usually you have a limited force you can apply. What happens to the moments if force stays the same but the length of the pencil fragement gets reduced?
 
your distance is decreasing from pivoted point, thus the total f*distance.. this should be greater then the limit.
 
I agree, less torque with reduced surface area means less tension being applied to the pencil ! If you place said pencil in a fixed place, such as two eye hole screws. Put the pencil into these holes, which are spaced about a inch apart and you use your fingers to break the pencil. The applied pressure doesn't change, it's only when you hold the pencil in your hand that we notice the force needed doubles which each snap of the pencil. Basically it's to do with surface area and torque applied, less area means less torque unless it's in a fixed position as described above.
 

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