Why Does Line Current Equal Effective Current in Polyphase Circuits?

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SUMMARY

The discussion centers on the relationship between line current and effective current in polyphase circuits, specifically addressing why line current equals I(eff) and line voltage equals V(eff). The confusion arises from the inclusion of wire resistance in the apparent power calculations, which affects the determination of line current. The participant highlights the importance of considering the total wire resistance when calculating power and current, emphasizing that overlooking this can lead to significant errors in analysis.

PREREQUISITES
  • Understanding of polyphase circuit theory
  • Familiarity with complex power (S) in electrical engineering
  • Knowledge of line-to-line and line-to-neutral voltage conversions
  • Basic principles of electrical resistance and its impact on power calculations
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  • Study the concept of complex power in polyphase systems
  • Learn about the impact of wire resistance on power distribution
  • Explore the calculations for line-to-neutral voltage conversions
  • Investigate the implications of ignoring resistance in power calculations
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Electrical engineers, students studying power systems, and professionals involved in circuit analysis and design will benefit from this discussion.

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I'm having some trouble understanding some parts of this question

attachment.php?attachmentid=24365&stc=1&d=1268534658.jpg


This is what I've been doing but I'm not quite sure why it works:

attachment.php?attachmentid=24366&stc=1&d=1268534658.jpg


I have some similar problems and have been getting the same problems with them. I don't know why the line current equals I(eff) and line voltage equals V(eff). Also why does V(an) = V(aA)+V(AN).
 

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Am I missing something, or is this problem impossible? You're given the line to line voltage at a point after the wire resistance, and the power given includes the load and the wire resistance. After you convert your line to line voltage to a line to neutral voltage, you have a voltage over the load, but you cannot use it to find the line current because of the inclusion of the line resistance in that apparent power given.

For example, you use [tex]S_{AN}[/tex] when the given was actually [tex]S_{AN} + S_{aA}[/tex]

Just think about it: you found the total wire resistance dissipated 1kW of energy, but you are ignoring its effects (which seem to be massive) when you found the line current by assuming it accounted for none of the total load's apparent power.

it would actually be:
[tex]1333 + j1000 = (V_{AN} + V_{aA}) I^*[/tex]

and we don't know VaA...
 

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