Why Does My Laplace Transform Calculation Differ from the Textbook's Result?

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Homework Help Overview

The discussion revolves around the calculation of Laplace transforms, specifically for functions involving exponentials and polynomials. Participants are examining their approaches to applying the Laplace transform definition and integration techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants describe their attempts to compute the Laplace transform using integration by parts and substitution methods. Questions arise regarding the handling of limits and the complexity of resulting integrals.

Discussion Status

Some participants have provided insights into potential errors in limit handling and suggested further use of integration by parts. There is an acknowledgment of the iterative nature of the problem-solving process, with one participant noting multiple integrations were necessary to reach a solution.

Contextual Notes

Participants mention specific functions and transformations, highlighting the challenges of integrating exponential functions combined with polynomial terms. The discussion reflects on the need for careful attention to detail in the integration process.

Eastonc2
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Homework Statement


f(t)=e^(t+7)

Homework Equations


£{f(t)}=∫e^(-st)f(t)dt

The Attempt at a Solution


so i insert my f(t) into the formula, came up with ∫e^(-st+t+7)dt
using u substitution, u=t(-s+1)+7, du=(-s+1)dt so it follows that 1/(-s+1)∫e^(u)du=e^(u)/(-s+1)
so I plug u back in, and should be able to find my answer from there, only I come up with an answer very different from the one in the book, which is e^(7)/(s-1)
Can anyone help me out?

So i figured it out, I set u=-1(t(-s+1)+7)=t(s-1)-7, and put e^-u inside the integral. turns out just making myself look at it a little longer worked out
 
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Eastonc2 said:

Homework Statement


f(t)=e^(t+7)


Homework Equations


£{f(t)}=∫e^(-st)f(t)dt


The Attempt at a Solution


so i insert my f(t) into the formula, came up with ∫e^(-st+t+7)dt
using u substitution, u=t(-s+1)+7, du=(-s+1)dt so it follows that 1/(-s+1)∫e^(u)du=e^(u)/(-s+1)
so I plug u back in, and should be able to find my answer from there, only I come up with an answer very different from the one in the book, which is e^(7)/(s-1)
Can anyone help me out?

You didn't show your work with the limits, which is where your error is. You need to either put the new u limits in your u answer or the t limits in your t answer.
 
ok, so I figured out that last one, now I'm having difficulty with £{t^(2)e^(-2t)}. putting it into the laplace definition I come up with ∫t^(2)e^(-t(s+2))dt. I've tried integration by parts, and come up with:
u=t^2, du=2t dt, dv=e^(-t(s+2))dt

and that's where i get stuck, i can't seem to figure out this integration. I've plugged it into wolfram, but that turns out with v=te^(-t(s+2)), which, when plugged back into the integration by parts, leaves me with a more complicated equation, involving the negative of my original integral.
 
You can always use integration by parts again,
 
changed a few things around, still using integration by parts, actually integrated by parts i think three times total, if I'm remembering last night correctly, to finally end up with the right answer. thanks
 

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