Why does ray a correspond to red and ray b to violet in this dispersion diagram?

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Ray a corresponds to red light, while ray b corresponds to violet light, despite ray a bending more. Higher frequency colors, like violet, have a higher index of refraction in silicate flint glass, causing them to bend more towards the normal upon refraction. The discussion highlights that refraction occurs at both sides of the glass, with both rays exiting parallel but shifted. Snell's Law explains the relationship between the angles of incidence and refraction, indicating that light bends more when transitioning to a medium with a higher refractive index. Ultimately, the bending behavior of the rays confirms that ray a is indeed red and ray b is violet.
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Homework Statement


Rays a and b are shown in the figure. Which corresponds to red and which to violet?
yf_Figure_33_47.jpg


The answer in mastering physics says that ray a corresponds to red. Why is this? I've read that colors with higher frequencies will bend more than those of lower frequencies. From what i can tell ray a is bending more so shouldn't a correspond to violet?

I was also looking through my book and found that violet colors have a higher index of refraction in silicate flint glass than do red ones. doesn't light with higher indexes bend more?
 

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upload_2017-11-11_10-25-17.png

The angle of incidence (alpha) and the angle of refraction (beta) both are angles enclosed by the rays with the normal of incidence, the red line in the figure. You see that b bends more towards the normal after refraction.
 

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is the reason your measuring the refraction angle from within the glass because the two rays seem to be parallel coming out of the glass?
 
Augustine Duran said:
is the reason your measuring the refraction angle from within the glass because the two rays seem to be parallel coming out of the glass?
Refraction happens to the rays at both sides of the glass. Leaving the glass, both rays have the same direction (they are parallel) only shifted.
Refraction means that the light ray, incident upon the interface between different media, will change direction. This change happens according to Snell's Law: n1sin(α)= n2 sin(β). If the ray is incident from air (refractive index n1=1) at the surface of glass (refractive index n2) sin(β)=sin(α)/n2. The angle of refraction changes more when the refractive index is higher.
 
So is it correct to say that both a and b are bending away from the normal at the RIGHT side of the glass at the same angle, that ray a is just shifted down?
 
Augustine Duran said:
So is it correct to say that both a and b are bending away from the normal at the RIGHT side of the glass at the same angle, that ray a is just shifted down?
Both rays, a and b are just shifted down with respect of the incident ray. The rays are bent away from the original direction inside the glass.
upload_2017-11-12_4-38-41.png
 

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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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