Why does sin(t)cos(t) = x(1-x)^{1/2}

  • Thread starter laura_a
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  • #1
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I'm working on a differential equation, and my answer is

sin(t)cos(t) which in the text, they jump from that straight to
[tex] x(1-x^2)^{\frac{1}{2}} [/tex]

I've forgotten a lot of what I learnt in my first few years of Uni and I just can't remember why they equal, I thouht it might be an identity, but I have looked on the net and can't find one... can someone please shed some light? Thanks
 

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  • #2
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Dont worry I worked it out
 
  • #3
George Jones
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I'm working on a differential equation, and my answer is

sin(t)cos(t) which in the text, they jump from that straight to
[tex] x(1-x^2)^{\frac{1}{2}} [/tex]

I've forgotten a lot of what I learnt in my first few years of Uni and I just can't remember why they equal, I thouht it might be an identity, but I have looked on the net and can't find one... can someone please shed some light? Thanks

What is [itex]x[/itex]?
 
  • #4
was there a u-substitution or something earlier on? cause taking either sin(t) as x, or cos(t) as x, would give the second equation when rewritten in terms of x.
 

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