- #1

albertrichardf

- 165

- 11

consider the following curve:

[tex] f(\theta) = \frac {I_0sin^2(n\theta/2)}{sin^2(\theta/2)} [/tex]

When the area over a cycle from ##0## to ##2π## is evaluated it gives ##(2πnI_0)##. This is exactly ##\frac {I_{max} + I_{min}}{2}## , since

##I_{min}## is ##0##. Is this a coincidence, or is there a reason behind the area under the curve is the same as this value?

Thank you for your answers.