Why Does the Exponential Calculation in My RC Circuit Equation Return 1?

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Homework Help Overview

The discussion revolves around an RC circuit problem, specifically focusing on the equation for a discharging capacitor. The original poster is encountering an issue with the exponential calculation consistently returning a value of 1.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the correct interpretation of the equation, questioning whether the exponential term is being calculated correctly and discussing the need for proper parentheses in the expression.

Discussion Status

Some participants have provided clarification on the equation's structure, suggesting that the original poster may need to adjust the placement of brackets to achieve the correct calculation. There appears to be a productive exchange regarding the interpretation of the equation.

Contextual Notes

The original poster's calculations are constrained by the specific format of the equation and the potential for misinterpretation due to the lack of parentheses. The discussion highlights the importance of notation in mathematical expressions.

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Homework Statement



I'm trying to use the equation for charging capacitor that's discharging, and I can't get the answer right. On the calculator it keeps showing as 1.

Homework Equations



I(t) = -(1.96) [e^((-9.0*10^(-6)) / (1300)(2.0*10^(-9)))]

The Attempt at a Solution



My problem is that the exponential part keeps coming out as the value 1 when I input it into the calculator. I need help on solving the exponential part.
 
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Is the equation $$ -1.96 \exp{\frac {-9.0*10^{-6}}{1300*2.0*10^{-9}}} $$ or is it $$ -1.96 \exp({\frac {-9.0*10^{-6}}{1300}2.0*10^{-9}}) $$?
 
the first one... e^(-t/RC)
 
The way you typed it, however, it will be interpreted as #2. You need additional brackets to enforce #1, OR you must use the division operation twice.
 
oh. thank you for the clarity. it works.:smile::smile:
 

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