Why Does the Limit of ln(x²-9) Approach -∞ as x Approaches 3?

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The limit of ln(x²-9) approaches -∞ as x approaches 3 from the right (x > 3) because the expression inside the logarithm, x²-9, approaches 0, leading to the logarithm of a number approaching 0, which results in -∞. The user initially miscalculated by evaluating values too close to 3 from the left instead of the right. Correct evaluations using x=3.01 and x=3.001 confirm the limit behavior. This demonstrates the importance of understanding one-sided limits in calculus.

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CrossFit415
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I'm on mobile so I won't use latex.

Lim x -> 3 ln(x^2-9)

My question is why limit approaches - infinite? When I plug in the numbers I get positive infinite.
 
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How did you get positive infinite?? Can you show me what you did?
 
Since I have to figure out x>3, I plugged in the values such as x=4 y=1.945, x=3.5 y=1.178, x=3.9 y=1.826. Whoops I found my mistake haha. I kept plugging in 3.9 and 3.9999 thinking it was closer to 3, when I should had plugged in 3.01 and 3.001. Thank you.
 

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